All categories

2 years ago

Amy says that the 9 in the number 900.876 is 1/1,000 the size of the 9 in 6.91. Is she correct? How do you know?

Mathematics

2 answers:

Oksi-84 [34.3K]2 years ago

8 0

Answer:

Step-by-step explanation:

The 9 in 900.876 is 900 and the 9 in 6.91 is .9 and if you look at the place value, you'll see that 900 is larger than .9

Phoenix [80]2 years ago

4 0

Answer: The 9 in 900.876 is 900 and the 9 in 6.91 is .9 and if you look at the place value, you'll see that 900 is larger than 9. so no

You might be interested in

Please help ASAP I will appreciate it

kolbaska11 [484]

Answer:

2 i think

Step-by-step explanation:

8 0

2 years ago

Help please.!!

Dafna11 [192]

Answer: The answer is (y^2) to the power of -0.5

Step-by-step explanation:

8 0

2 years ago

How do I solve this?

vladimir1956 [14]

Answer:

3p³ + 2p² – 3p – 11

Step-by-step explanation:

From the question given above, the following data were obtained:

Side 1 (S₁) = –1(p + 5)

Side 2 (S₂) = 2(p² – 3)

Side 3 (S₃) = 3p³ – 2p

Perimeter (P) =?

The perimeter of the triangle can be obtained as follow

P = S₁ + S₂ + S₃

P = –1(p + 5) + 2(p² – 3) + 3p³ – 2p

Clear bracket

P = –p – 5 + 2p² – 6 + 3p³ – 2p

Rearrange

P = 3p³ + 2p² – 2p – p – 6 – 5

P = 3p³ + 2p² – 3p – 11

Therefore, the perimeter of the triangle is 3p³ + 2p² – 3p – 11

4 0

2 years ago

May someone help <3

skad [1K]

Answer:

x = 14

Step-by-step explanation:

4x + 2x + 6 = 90

Combine like-terms

6x + 6 = 90

6x = 84

x = 14

7 0

2 years ago

"A student made the following chart to prove that AB2 + BC2 = AC2.

katovenus [111]

Step 3 has an error.

Step-by-step explanation:

Similarity-criteria of triangles:

1. All the corresponding angles of two triangles should be equal.

2. The ratio between the corresponding sides of two triangles should be equal.

In $\triangle ABC$ and $\triangle BDC$

$\angle BAC = \angle DBC \\\angle ACB = \angle BCD$

All the angles of triangle are equal.

∴ $\triangle ABC \sim \triangle BDC$

Since, $\triangle ABC \sim \triangle BDC$

$\frac{AC}{BC}=\frac{AC}{DC}$

$BC^{2}=AC \times DC$

In $\triangle ABC$ and $\triangle BDA$ ,

$\fbox{\begin\\ \angle ABC= \angle BDA = 90^{\circ}\end{minispace}}$

$\fbox{\begin \\\angle BAC = \angle BAD\\\end{minispace}}$

$\angle ACB = \angle ABD$

All the angles of triangle are equal.

∴ $\fbox{\begin\triangle ABC \sim \triangle BDA \end{minispace}}$

∵ $\triangle ABC \sim \triangle BDA$

$\frac{AC}{AB}=\frac{AB}{AD}$

$AB^{2}=AC \times AD$

Now, $AB^{2}+BC^{2}$ can be simplified as,

$AB^{2}+BC^{2}=AC \times AD+AC \times DC\\AB^{2}+BC^{2}=AC(AD+DC)\\AB^{2}+BC^{2}=AC(AC)\\AB^{2}+BC^{2}=AC^{2}$

Learn more:

1. Find the height of the triangle?

brainly.com/question/12989306

2. Which undefined term is needed to define an angle? brainly.com/question/3717797

3. Look at the figure, which trigonometric ratio should you use to find x? brainly.com/question/9880052

Answer Details

Grade: Junior High School

Subject: Mathematics

Chapter: Triangle

Keywords: triangle, similar, similarity, ratio of sides, right triangle, similar triangle, ratio of sides, equal angles, square of hypotenuse, sum, square of legs, sum of square of legs

8 0

2 years ago