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Artist 52 [7]
3 years ago
6

Plz help due soon!!!

Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0

Answer:

Option A: 6 to 9 , 9/12 is the correct answer.

Step-by-step explanation:

The equivalent ratios simplify to same simple ratio.

In case of this question, we have to check which to the ratios doesn't simplify to 3:4 or 3/4

Option A:

6 to 9 , 9/12

6 to 9 can be written as:

=\frac{6}{9}\\= \frac{2}{3} \neq \frac{3}{4}

9/12 simplifies to 3/4

But as one of the ratio doesn't simplify to 3:4 which means 6 to 9 is not equivalent to 3:4

Hence,

Option A: 6 to 9 , 9/12 is the correct answer.

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The answer is A because the x has different numbers
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Here is a linear equation: y = 1/4x +5/4
docker41 [41]

Step-by-step explanation:

(1,1.5) is the solution but (12,4) is not the solution of given equation.

1.5=1/4×1+5/4(which is true)

4=1/4×12+5/4(which is false)

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A teacher needs to find out how many seventh-grade students will be going on a field trip. Which best describes the population t
kherson [118]

Answer:

In statistics , the population is the set of all possible observations as per the researcher's objective .

For example if a researcher wants to find the average height of teenager of age group between 13 year and 15 years in Seattle, he will need the data of the population of height of teenager of age group between 13 year and 15 years in Seattle.

Here , A teacher needs to find out how many seventh graders will be going on a field trip.

Clearly as per her objective she need the data of all seventh graders .

So , the best describes the population that the teacher should survey would be : All seventh graders.

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Step-by-step explanation:

4 0
3 years ago
For the given term, find the binomial raised to the power, whose expansion it came from: 15(5)^2 (-1/2 x) ^4
Elina [12.6K]

Answer:

<em>C.</em> (5-\frac{1}{2})^6

Step-by-step explanation:

Given

15(5)^2(-\frac{1}{2})^4

Required

Determine which binomial expansion it came from

The first step is to add the powers of he expression in brackets;

Sum = 2 + 4

Sum = 6

Each term of a binomial expansion are always of the form:

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

Where n = the sum above

n = 6

Compare 15(5)^2(-\frac{1}{2})^4 to the above general form of binomial expansion

(a+b)^n = ......+15(5)^2(-\frac{1}{2})^4+.......

Substitute 6 for n

(a+b)^6 = ......+15(5)^2(-\frac{1}{2})^4+.......

[Next is to solve for a and b]

<em>From the above expression, the power of (5) is 2</em>

<em>Express 2 as 6 - 4</em>

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

By direct comparison of

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

and

(a+b)^6 = ......+15(5)^{6-4}(-\frac{1}{2})^4+.......

We have;

^nC_ra^{n-r}b^r= 15(5)^{6-4}(-\frac{1}{2})^4

Further comparison gives

^nC_r = 15

a^{n-r} =(5)^{6-4}

b^r= (-\frac{1}{2})^4

[Solving for a]

By direct comparison of a^{n-r} =(5)^{6-4}

a = 5

n = 6

r = 4

[Solving for b]

By direct comparison of b^r= (-\frac{1}{2})^4

r = 4

b = \frac{-1}{2}

Substitute values for a, b, n and r in

(a+b)^n = ......+ ^nC_ra^{n-r}b^r+.......

(5+\frac{-1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ ^6C_4(5)^{6-4}(\frac{-1}{2})^4+.......

Solve for ^6C_4

(5-\frac{1}{2})^6 = ......+ \frac{6!}{(6-4)!4!)}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6!}{2!!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5*4!}{2*1*!4!}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{6*5}{2*1}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+ \frac{30}{2}*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15*(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^{6-4}(\frac{-1}{2})^4+.......

(5-\frac{1}{2})^6 = ......+15(5)^2(\frac{-1}{2})^4+.......

<em>Check the list of options for the expression on the left hand side</em>

<em>The correct answer is </em>(5-\frac{1}{2})^6<em />

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3 years ago
What is 5d - 10 = 20​
algol [13]

Answer:

d=6

Step-by-step explanation:

move all terms that don't contain d to the right side and solve.

6 0
3 years ago
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