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Ivanshal [37]
3 years ago
12

Solve these two equations

Mathematics
1 answer:
tangare [24]3 years ago
8 0

Answer:

a.(2/7,31/7) b.(97,71)

Step-by-step explanation:

im not writing all the work i did its just substitution of the value of x and y from the second equation to the first

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Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=
Ganezh [65]

Answer:

y(1+x)+x-5\ln xy=C

Step-by-step explanation:

Consider the given differential equation is

(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1

(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y

(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx

Taking all variables on right sides.

(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0

(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0

Let as assume,

M=-\frac{5}{x}+1+y and N=1-\frac{5}{y}+x

Find partial derivatives \frac{\partial M}{\partial y} and \frac{\partial N}{\partial x}

\frac{\partial M}{\partial y}=1 and \frac{\partial N}{\partial x}=1

Since \frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}, therefore the given differential equation is exact.

The solution of the exact differential equation is

\int Mdx+\int N(\text{without x)}dy=C

\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C

yx-5\ln x+x+y-5\ln y=C

y+x+xy-5\ln x-5\ln y=C

y(1+x)+x-5(\ln x+\ln y)=C

y(1+x)+x-5\ln xy=C

7 0
3 years ago
F(x) = x2 + 2x-5<br> g(x) = -3/2 - 4x + 1<br> What is f(x) – g(x)?
NeX [460]

Step-by-step explanation:

Start by finding (fog)(x)

To find this function, substitute x=

x−1

4

That is g(x) into f(x)

⇒(f∘g)(x)=(

x−1

4

)

2

−2(

x−1

4

)+5

=

(x−1)

2

16

−

x−1

8

+5

Now substitute x=3

⇒(f∘g)(3)=

(3−1)

2

16

−

3−1

8

+5

=

4

16

−

2

8

+5=4−4+5=5.

Hope it helps:)

6 0
3 years ago
Númer 9 and 10 please help
vredina [299]
9. -1,07, 1/2. 3........it is all I could see

10. -V25= -5
-5, -4,3, 0, V15, 4,2
8 0
3 years ago
Which represents where f(x) = g(x)?
Lyrx [107]

The <em><u>correct answer</u></em> is:

f(2) = g(2) and f(0) = g(0)

Explanation:

If f(x) = g(x), this means the values of the functions are the same when using the same numbers.  That means if we use 2 for x, then f(2) would need to be equal to g(2); if we use 0 for x, then f(0) would need to be equal to g(0).  This is the case in this option, so this option is correct.

3 0
3 years ago
Read 2 more answers
If AJKL: ABCA, which statement must be true?
Oksana_A [137]

Answer:CACA

CACA

Step-by-step explanation:

(im not sure if there is a picture of the question but i cant see it)

8 0
3 years ago
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