Because....
of means *
1/2* 2= 2/2 reduce it
you will get one
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
2nd or 3rd one
Step-by-step explanation:
I say that because the equation is over -3 for both.
Hope this helps you! :)
It doesn't add up to 360 degrees
Answer:
2*√2
Step-by-step explanation:
You need to use the trigonometrical function of angle (You should use the side sqrt2 and x to find the x). Take any acute angle (for example, 60 degrees)
The cos of this angle is equal to the ratio of adjoined leg (sqrt2) to the hypotenude (the side opposite to right angle, it is x)
cos60degrees= sqrt2/ x
1/2= sqrt2/x
x= 2*sqrt2= 2*√2
