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Sergeeva-Olga [200]
3 years ago
14

Which correctly compares 13 and 13.0? A) 13.0 > 13 B) 13 < 13.0 C) 13.0 = 13 D) 13 > 13.0

Mathematics
1 answer:
ladessa [460]3 years ago
3 0

Answer:

C) 13.0 = 13

13.0 is equal to 13.

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A simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and
Brrunno [24]

Answer:

.b. It is one‐half as large as when n = 100.

Step-by-step explanation:

Given that a  simple random sample of 100 batteries is selected from a process that produces batteries with a mean lifetime of 32 hours and a standard deviation of 3 hours.

i.e. s = 0.3

we obtain se of sample by dividing std devitation by the square root of sample size

i.e. s= \frac{3}{\sqrt{n} }

when n =100 this = 0.3 and

when n =400 this equals 0.15

We find that when sample size is four times as large as original, std deviation becomes 1/2 of the original

Correction option is

.b. It is one‐half as large as when n = 100.

7 0
3 years ago
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Tcecarenko [31]

- 5 \sqrt{49 - 8a =  - 35}  \\  \\ 1. \:  - 8a = 0 \\  \\ 2. \:  \frac{ - 8a}{ - 8} =  \frac{0}{ - 8}   \\ a = 0

7 0
3 years ago
Which statement is best represented by the inequality c greater-than 3 and one-half?
luda_lava [24]

Answer: Chef Andre used more than 3 and one-half cups of flour.

Step-by-step explanation:

This is the > ‘greater than sign. For the question, we are to get the inequality that shows that"c is greater-than 3 and one-half".

Let Chef Andre be represented by c. Greater than is used to denote a situation when something is."more than" another thing. In this scenario,

Chef Andre used more than 3 and one-half cups of flour. This can be represented as C > 3 1/2.

This is the correct answer.

3 0
3 years ago
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In four years, 40% of a radioactive element decays. Find its half-life. Round to one decimal place.
White raven [17]

To find the answer, use k = \frac{2.303 }{ 4} (log\frac {100 }{ 40}) , and then use the equation t=\frac{.693}{k} To find it's half life.

5 0
3 years ago
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Need help please help me
Ostrovityanka [42]
The solution is the point of intersection between the two equations.

Assuming you have a graphing calculator or a program to lets you graph equations (I use desmos) you simply put in the equetions and note down the coordinates of the point of intersection.

In the graph the first equation is in blue and the second in red.

The point of intersection = the solution = (-6 , -1)



If you dont have access to a graphing calculator you could draw the graphs by hand;

1) Draw a table of values for each equation; you do this by setting three or four values for x and calculating its image in y (you can use any values of x)

y = 0.5 x + 2 (Im writing 0.5 instead of 1/2 because I find its easier in this format)

x | y
-1 | 1.5 * y = 0.5 (-1) + 2 = 1.5
0 | 2 * y = 0.5 (0) + 2 = 2
1 | 2.5 * y = 0.5 (1) + 2 = 2.5
2 | 3 * y = 0.5 (2) + 2 = 3

y = x + 5

x | y
-1 | 4 * y = (-1) + 5 = 4
0 | 5 * y = (0) + 5 = 5
1 | 6 * y = (1) + 5 = 6
2 | 7 * y = (2) + 5 = 7

2) Plot these point on the graph
I suggest to use diffrent colored points or diffrent kinds of point markers (an x or a dot) to avoid confusion about which point belongs to which graph

3) Using a ruler draw a line connection all the dots of one graph and do the same for the other

4) The point of intersection is the solution

8 0
3 years ago
Read 2 more answers
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