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3 years ago

4x - 2y = 5 and y = 3x - 1

Mathematics

1 answer:

Talja [164]3 years ago

7 0

Answer:

4x_2y=5

4x=5+2y

x=5+2y/5

now, y=3x_1

putting value of x in second question

In this way you can do

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(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun

finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.

f(a) = d, f(b) = b, f(c) = c, f(d) = d.

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3 years ago

Julia enjoys shooting paper balls into the wastebasket across her office. She misses the first shot 50% of the time. When she mi

Marianna [84]

Answer:

a) Probability that Julia misses two shots in a row = $\frac{1}{2}\frac{1}{5} =\frac{1}{10}$

b) We can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

$P(X \geq 1)$

And using the complement rule we have this:

$P(X \geq 1) = 1-P(X$

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

$P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}$

Step-by-step explanation:

Part a

For this case we know that Julia enjoys shooting paper balls into the basket across her office.

She misses the first shot 50% of the time.

Probability that Julia misses the first shot = $\frac{1}{2}$

When she misses on the first shot, she misses the second shot 20% of the time.

Probability that Julia misses the second shot = $\frac{1}{5}$

For this case we need to find the probability of missing two shots in a row

So we can multiple the two probabilities like this

Probability that Julia misses two shots in a row = $\frac{1}{2}\frac{1}{5} =\frac{1}{10}$

Part b

For this case we want probability of making at least one successful throw

And we can use the complement rule on this case. Let X the number of shoots successful, we want this probability:

$P(X \geq 1)$

And using the complement rule we have this:

$P(X \geq 1) = 1-P(X$

And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:

$P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}$

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3 years ago

Can anyone help me this was literally due over a week ago

mixer [17]

Answer:

You multiply 5 by 1/5 to get 1. So with 2x, you multiply by 1/(2x) to get 1. That's about all you know, since we only know that x is positive.

Step-by-step explanation:

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