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Delvig [45]
2 years ago
13

Find the missing length in the image below

Mathematics
2 answers:
Ket [755]2 years ago
7 0

Answer:

1 length ityoughkdds hshlkb

ollegr [7]2 years ago
4 0

Let it be x

\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{3}{6}

  • Use cross multiplication

\\ \sf\longmapsto 6x=10(3)

\\ \sf\longmapsto 6x=30

\\ \sf\longmapsto x=\dfrac{30}{6}

\\ \sf\longmapsto x=5

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Find the measure of the indicated angle to the nearest degree
Alisiya [41]

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

     sin Ф = 0.806

          Ф = 53.66°

17) cos Ф = 11/34

    cos Ф = 0.324

          Ф = 71.12°

18) sin Ф = 21/40

     sin Ф = 0.525

           Ф = 31.67°

19) cos Ф = 6/14

     cos Ф = 0.429

          Ф = 64.62°

20) cos Ф = 38/39

      cos Ф = 0.974

            Ф = 13°

3 0
3 years ago
Question is: Solve -7(x+6)=4(x+6)
Alina [70]

\huge\boxed{x=-6}

Hey there! Our goal here is to isolate the variable on one side of the equation.

\begin{aligned}-7(x+6)&=4(x+6)&&\smash{\Big|}&&\textsf{Start with the original equation.}\\-7x+(-7)(6)&=4x+4(6)&&\smash{\Big|}&&\textsf{Distribute.}\\-7x-42&=4x+24&&\smash{\Big|}&&\textsf{Multiply.}\\-7x-4x&=24+42&&\smash{\Big|}&&\textsf{Move the terms.}\\-11x&=66&&\smash{\Big|}&&\textsf{Combine like terms.}\\x&=\boxed{-6}&&\smash{\Big|}&&\textsf{Divide both sides by $-11$.}\end{aligned}

8 0
2 years ago
Read 2 more answers
What is the vertex of the function x2 - 14x - 95 = 0?
monitta
I hope everythink is clearly :) If not just ask :)


answer for your question is starting when x^2-14x-95=0. Just Ignore this above this.

6 0
3 years ago
A submarine travels 6.6 km due West from its base and then turns and travels due South for 3.9
geniusboy [140]

Answer:

7.7 km

Step-by-step explanation:

The submarine's path from its base forms a right triangle when its final position is "connected" to the base. We know that the right triangle has legs of 6.6 km and 3.9 km, and we need to find the length of its hypotenuse. To do so, we can use the Pythagorean Theorem, which states that in a right triangle, a^{2}+b^{2} =c^{2}, where a and b are the lengths of the triangle's legs and c is the length of the triangle's hypotenuse. In this case, we know what a and b are, and we need to solve for c, so after substituting the given values of a and b into a^{2}+b^{2} =c^{2} to solve for c, we get:

a^{2}+b^{2} =c^{2}

6.6^{2} +3.9^{2} =c^{2} (Substitute a=6.6 and b=3.9 into the equation)

43.56+15.21=c^{2} (Evaluate the squares on the LHS)

58.77=c^{2} (Simplify the LHS)

c^{2}=58.77 (Symmetric Property of Equality)

\sqrt{c^{2} } =\sqrt{58.77} (Take the square root of both sides of the equation)

c=7.7,c=-7.7 (Simplify)

c=-7.7 is an extraneous solution because you can't have negative distance, if that makes sense, so therefore, the submarine is approximately 7.7 km away from its base. Hope this helps!

7 0
3 years ago
3. *
Sati [7]

Answer:

A first numbers cant be same

5 0
2 years ago
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