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3 years ago

This circle is centered at the origin, and the length of its radius is 8. what is the equation of the circle?

2 answers:

8 0

Hello :
note :

an equation of the circle Center at the A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 b = 0 r =8
the equation of the circle is : x²+y² = 64

klasskru [66]3 years ago

8 0

Answer: The required equation of the circle is $x^2+y^2=64.$

Step-by-step explanation: We are given to find the equation of a circle with center at the origin and radius of length 8 units.

We know that

the equation of a circle with center at the point (g, h) and radius of length r units is given by

$(x-g)^2+(y-h)^2=r^2.$

Here,

center, (g, h) = (0, 0) and radius, r = 8 units.

Therefore, the equation of the circle will be

$(x-0)^2+(y-0)^2=8^2\\\\\Rightarrow x^2+y^2=64.$

Thus, the required equation of the circle is $x^2+y^2=64.$

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taurus [48]

Answer:

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Explanation:

The diagram representing the question is shown in the attached image

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Now, in the given diagram:

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3 years ago

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gtnhenbr [62]

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3 years ago

George plans to cover his circular pool for the upcoming winter season. The pool has a diameter of 20 feet and the cover extends

MariettaO [177]

For the circular cover we have:

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<h3>How to get the area of the cover?</h3>

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In this case, the diameter of the pool is 20ft, then the radius is:

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B) now we want to get the length of the rope, we know that the rope runs along the cover, then the length of the rope must be equal to the circumference of the cover.

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