Hello,

x=-3 is the vertical asymptote.
Answer:
and independent variable It is a variable that stands alone and isn't changed by the other variables you are trying to measure. For example, someone's age might be an independent variable. and a Just like an independent variable, a dependent variable is exactly what it sounds like. It is something that depends on other factors. For example, a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it.
Answer:
Which expression is equal to
?
The correct answer is B.
![4a^{2}b^{2}c^{3}(\sqrt[3]{b})](https://tex.z-dn.net/?f=4a%5E%7B2%7Db%5E%7B2%7Dc%5E%7B3%7D%28%5Csqrt%5B3%5D%7Bb%7D%29)
Step-by-step explanation:
Inside of the radical you have
. If you find the cube root of that, you get 4a^2. Go ahead and write that outside of the parenthesis:


](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%28%7Bb%5E%7B7%7Dc%5E%7B9%7D%7D%29)
If you re-write what is inside of the radical, you get:
![4a^{2}(\sqrt[3]{b^{3}*b^{3}*b^{1}*c^{3}*c^{3}*c^{3} }](https://tex.z-dn.net/?f=4a%5E%7B2%7D%28%5Csqrt%5B3%5D%7Bb%5E%7B3%7D%2Ab%5E%7B3%7D%2Ab%5E%7B1%7D%2Ac%5E%7B3%7D%2Ac%5E%7B3%7D%2Ac%5E%7B3%7D%20%20%20%7D)
Basically I expanded what was inside of the radical so I could find the cube roots of b^7 and c^9.
Now, take the cube root of b^7:
![4a^{2}b^{2} (\sqrt[3]b*c^{3}*c^{3}*c^{3} })](https://tex.z-dn.net/?f=4a%5E%7B2%7Db%5E%7B2%7D%20%28%5Csqrt%5B3%5Db%2Ac%5E%7B3%7D%2Ac%5E%7B3%7D%2Ac%5E%7B3%7D%20%20%20%7D%29)
Notice how I could only factor out the two "b^3" that were inside the radical symbol, and how I left the b^1 inside the radical symbol because I couldn't factor it out.
Let's now get the cube root of c^9. Since it's a perfect cube, there won't be any "c"s left inside of the radical symbol:
![4a^{2}b^{2}c^{9}(\sqrt[3]b)](https://tex.z-dn.net/?f=4a%5E%7B2%7Db%5E%7B2%7Dc%5E%7B9%7D%28%5Csqrt%5B3%5Db%29)
Answer: A
Explanation:
a = -8
d = +4
an = a + ( n - 1 ) d
= -8 + ( n - 1 ) 4
So;
= -8 + 4 ( n - 1 )