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arsen [322]
3 years ago
6

A particular telephone number is used to receive both voice calls and fax messages. Suppose that 25% of the incoming calls invol

ve fax messages, and consider a sample of 25 incoming calls. What is the probability that
a. At most 6 of the calls involve a fax message?
b. Exactly 6 of the calls involve a fax message?
c. At least 6 of the calls involve a fax message?
d. More than 6 of the calls involve a fax message?
e. What is the expected number of calls among the 25 that involve a fax message?
f. What is the standard deviation of the number among the 25 calls that involve a fax message?
g. What is the probability that the number of calls among the 25 that involve a fax transmission exceeds the expected number by more than 2 standard deviations?
Mathematics
1 answer:
Andre45 [30]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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Answer:

x^3 +8x^2 +13

Step-by-step explanation:

(6x^2 - 3 + 5x^3) - (4x^3 - 2x^2 - 16​)

Distribute the minus sign

6x^2 - 3 + 5x^3 -4x^3 + 2x^2 + 16​

Combine like terms

x^3 +8x^2 +13

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A 748-N man stands in the middle of a frozen pond of radius 4.0 m. He is unable to get to the other side because of a lack of fr
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Answer:

The man will take 64 seconds to reach to the south shore of the frozen pond.

Step-by-step explanation:

Given:

Weight of the man = 748 N      Mass of the man,(m)= \frac{W}{g} = \frac{748}{9.8} = 76.32 kg

Radius of the pond (r) = 4 m

Mass of the textbook = 1.2 kg

Velocity at which the textbook is thrown = 4 ms^1

We have to find the velocity of the man after the throw.

Let the velocity is V_m .

Now using law of conservation of momentum we can find the V_m value.

m_(_b_)V_b_(_i_) +m_(_m_)V_m_(_i_) =m_(_b_)V_b_(_f_)+m_(_m_) V_m_(_f_)

Considering V_m_(_f_)=V_m

And initial velocity of both the man and book i.e V_b_(_i_)=0,\ V_m_(i_)=0

So,

⇒ 0 =m_(_b_)V_b_(_f_)+m_(_m_) V_m

⇒ Plugging the values.

⇒ V_m=-\frac{m_(_b_)V_b_(_f_)}{m_(_m_)}

⇒ V_m=-\frac{1.2\times 4}{76.32}

⇒ V_m=-0.062 ms^-1

Here the negative velocity is meant for opposite direction of the throw.

Numerically we will write, V_m = 0.062

With this velocity the man will move towards south.

We have to calculate the time taken by the man to move to its south shore.

And we know velocity(v)\times time(t) = distance(d)

Let the time taken be t and v\times t = d and d=r then, V_m\times t=r

Then

⇒ t=\frac{radius\ (r)}{V_m}

⇒ Plugging the values.

⇒ t=\frac{4}{0.062}

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The man will take 64 seconds to reach to the south shore of the frozen pond (circular).

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