20 + 1.5 = 21.5
- 2 = 19.5
so hourly he gets paid $19.50
Answer:
h = 13.333 +693.333/r
Step-by-step explanation:
For h hours, Brandee's pay will be ...
pay = 40r +(h -40)(1.5r) . . . . 40 hours at rate r + overtime (h-40) hours at 1.5r
pay = 40r +1.5hr -60r . . . . . eliminate parentheses
pay = 1.5hr -20r . . . . . . . . . . collect terms
Solving for h, we have ...
pay +20r = 1.5hr . . . . . . . . . . add 20r
h = (pay +20r)/(1.5r) . . . . . . . . divide by 1.5r
For the given pay of 800 +240 = 1040, we have ...
h = (1040 +20r)/(1.5r)
h = 13.333 +693.333/r . . . . . simplify to 2 terms
_____
<em>Additional comments</em>
You need to know r to find the number of hours Brandee worked. She got paid $800 for a presumed 40-hours of regular time, so made r = $20 per hour. The above formula will tell you she worked 48 hours in the pay period.
Check the Wronskian determinant:

The determinant is not zero, so the solutions are indeed linearly independent.
Answer:
A
Step-by-step explanation:
the height a creates with half of the baseline (5) and a leg (10) a right-angled triangle, and we can use Pythagoras to calculate a.
c² = a² + b²
c being the Hypotenuse (the side opposite of the 90° angle, so in our case the 10 side).
10² = a² + 5²
100 = a² + 25
75 = a²
a = sqrt(75) = sqrt(3×25) = 5×sqrt(3)
the correct question is
What values of b satisfy 3(2b+3)^2 = 36
we have

Divide both sides by 

take the square root of both sides





therefore
the answer is
the values of b are

