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3 years ago

12

Alisha has a 15000 car loan with 6 percent interest rate that is compounded annually how much will she have paid at the end of t

he five year loan term

1 answer:

svetlana [45]3 years ago

7 0

A=p(1+r)^t
A=15,000×(1+0.06)^(5)
A=20,073.38

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How do I solve this equation using long polynomial division?

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2 years ago

Kerry has a bag containing white and yellow marbles. Kerry randomly selects one marble, records the result, and returns the marb

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Answer:

The probability that next selection is yellow marble = 63% .

Step-by-step explanation:

Given the selection of yellow marbles = 41 times.

The selection of white marble = 24 times.

Total number of selections made = 65

Now calculate the probability that the next selection will be the yellow marble. Therefore, the probability of getting yellow marble can be determined by dividing the yellow selection by total number of selections.

$\text{P(yellow)} = \frac{ \text{The selection of yellow marbles} }{ \text{ Total number of slections }} \\\text{P(yellow)} = \frac{41}{65} = 0.63 \ or \ 63 \ percent$

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3 years ago

Read 2 more answers

At an effective annual interest rate of i > 0, each of the following two sets of payments has present value K: (i) A payment

IgorLugansk [536]

Answer:

The present value of K is, $K=251.35$

Step-by-step explanation:

Hi

First of all, we need to construct an equation system, so

$(1)K=\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}$

$(2)K=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

Then we equalize both of them so we can find $i$

$(3)\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}}$

To solve it we can multiply $(3)*(1+i)^{4}$ to obtain $(1+i)^{4}*(\frac{169}{(1+i)} +\frac{169}{(1+i)^{2}}=\frac{225}{(1+i)^{2}} +\frac{225}{(1+i)^{4}})$ , then we have $225(1+i)^{2}+225=169(1+i)^{3}+169(1+i)^{2}$ .

This leads to a third-grade polynomial $169i^{3}+451i^{2}+395i-112=0$ , after computing this expression, we find only one real root $i=0.2224$ .

Finally, we replace it in (1) or (2), let's do it in (1) $K=\frac{169}{(1+0.2224)} +\frac{169}{(1+0.2224)^{2}}\\\\K=251.35$

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The answer for part a would be 130

the answer for part b would be 60

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