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Xelga [282]
3 years ago
9

Task 1

Engineering
1 answer:
andrew-mc [135]3 years ago
4 0

Answer:

I dont understand your question.

Explanation:

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Which of the following approaches to lean engineering consists of teams of people from different departments sharing
AURORKA [14]

Answer:

PDSA, where you work as a group

Explanation:

8 0
3 years ago
A ring-shaped seal, made from a viscoelastic material, is used to seal a joint between two rigid pipes. When incorporated in the
scoundrel [369]
I’m not sure what this question is talking about. I will get back to you later on this let me rethink it. 2.22578
3 0
3 years ago
Q#1: Provide an example of a software project that would be amenable to the following models. Be specific. a. Waterfall b. Proto
mote1985 [20]

Answer:

Waterfall model

Explanation:

The waterfall model is amenable to the projects. It focused on the data structure. The software architecture and detail about the procedure. It will interfere with the procedure. It interfaces with the characterization of the objects. The waterfall model is the first model that is introduced first. This model also called a linear sequential life cycle model.

The waterfall model is very easy to use. This is the earliest approach of the SDLC.

There are different phase of the waterfall:

  • Requirement analysis
  • System Design
  • Implementation
  • Testing
  • Deployment
  • Maintenance
4 0
3 years ago
A motor vehicle engine operating with a diesel engine takes in atmospherics air at a temperature of 30°C and pressure of 1 bar.
nydimaria [60]

Answer:

η=0.568

Explanation:

At inlet condition

temperature = 30 C and pressure P=1 bar

The maximum temperature = 13456 C

Compression ratio r= 12

We know that for process 1-2

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{303}=12^{1.4 -1}

T_2=818.68 K

Now for process 2-3

\dfrac{T_3}{T_2}=\dfrac{V_3}{V_2}

\dfrac{273+1345}{818.86}=\dfrac{V_3}{V_2}

\dfrac{V_3}{V_2}=1.97

So the cut off ratio ρ=1.97

Efficiency of diesel engine

\eta =1-\dfrac{\rho ^{\gamma}-1}{r^{\gamma -1}\gamma \left (\rho -1\right )}

Now put the values

\eta =1-\dfrac{1.97 ^{1.4}-1}{12^{1.4-1}\times 1.4\times \left (1.97 -1\right )}

   ⇒η=0.568

So the efficiency is 56.8%.

4 0
3 years ago
Problem
anzhelika [568]

Answer:

In the clevis shown in Fig. 1-11b, find the minimum bolt diameter and the minimum thickness of each yoke that will support a load P = 14 kips without exceeding a shearing stress of 12 ksi and a bearing stress of 20 ksi.

127-clevis-double-shear-bolt.gif

Solution 127

Hide Click here to show or hide the solution

127-fbd-clevis-double-shear-bolt.gifFor shearing of rivets (double shear)

P=τA

14=12[2(14πd2)]

d=0.8618in → diameter of bolt answer

For bearing of yoke:

P=σbAb

14=20[2(0.8618t)]

t=0.4061in → thickness of yoke answer

3 0
3 years ago
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