Sketch T-s and p-v diagrams for the Diesel cycle.
1 answer:
Answer:
Diesel cycle:
All diesel engine works on diesel cycle.It have four processes .These four processes are as follows
1-2.Reversible adiabatic compression
2-3.Heat addition at constant pressure
3-4.Reversible adiabatic expansion
4-1.Heat addition at constant volume
When air inters in the piston cylinder after that it compresses and gets heated due to compression after that heat addition take place at constant pressure after that power is produces when piston moves to bottom dead center.
From the diagram of P-v And T-s we can understand so easily.
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Answer:
Check the explanation
Explanation:
The Total pressure is the overall of fixed or static pressure p, the dynamic pressure q, as well as gravitational head. Total pressure can also be referred to as the measure of the overall energy of the airstream, and is the same to static pressure plus velocity pressure.
kindly check the step by step solution in the attached image below to Determine the (P0/Pt) values corresponding to the 1st, 2nd, and 3rd critical points.
Answer:
So % increment in tool life is equal to 4640 %.
Explanation:
Initially n=0.12 ,V=130 m/min
Finally C increased by 10% , V=90 m/min
Let's take the tool life initial condition is and when C is increased it become
.
As we know that tool life equation for tool
At initial condition ------(1)
At final condition -----(2)
From above equation
So increment in tool life =
=
So % increment in tool life is equal to 4640 %.
Answer:
45 Mpa
Explanation:
The maximum shear stress, is given by
Where T is the torque and d is the diameter.
Substituting 29820.586 N.m for T and 0.15m for d then we obtain
Answer:
a) The slip coefficient is 0.9
b) Blade tip speed is 345.57 m/s
c) Stagnation temperature exiting the impellor is 416.84 k
d) Exit flow velocity is 84.88 m/s
e) Exit flow angle is 76.2°
f) Exit static temperature is 353.84 k
g) Impellor exit Mach number is 0.943
Explanation:
Flow at entry is axial α₁ = 0
Tagential velocity at entry = 0
Blade at exit is radial β₂ = 0
μ₂ =
