To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.
The stagnation temperature can be defined as

Where
T = Static temperature
V = Velocity of Fluid
Specific Heat
Re-arrange to find the static temperature we have that



Now the pressure of helium by using the Adiabatic pressure temperature is

Where,
= Stagnation pressure of the fluid
k = Specific heat ratio
Replacing we have that


Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa
<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>
Answer:
Work done by the fluid in the piston=164.5kJ/kg
Specific gas constant= 0.263 kJ/kg K
Molecular weight of gas= 31.54 kmol
Answer:
10.984mm
Explanation:
by elastic modulus
stress=modulus of elasticity*strain
stress=loading/area area" cross-section"
11mm=0.011m
area=π(d/2)^2=π(0.011/2)^2=9.503*10^-5 square meter
stress=55000/(9.503*10^-5)=578.745 MPa
convert MPa and GPa to pascal.
strain=stress/modulus=(578.745*10^6)/(125*10^9)=0.00463............axial strain
v=Poisson ratio
lateral strain=(-v)*axial strain= -0.31*0.00463
lateral strain= -1.4353*10^-3=change in diameter/ original diameter
change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m
negative indicates decrease in diameter.
decrease in dia.=0.01578mm
new diameter=11-0.01578= 10.984mm
Answer:
This is False because people can have more than 1