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inysia [295]
3 years ago
9

A motor vehicle engine operating with a diesel engine takes in atmospherics air at a temperature of 30°C and pressure of 1 bar.

During combustion, the maximum obtainable temperature is 1345°C. Calculate (a) the air standard (b) thermal efficiency of this diesel engine if the compression ration is 24/2.

Engineering
1 answer:
nydimaria [60]3 years ago
4 0

Answer:

η=0.568

Explanation:

At inlet condition

temperature = 30 C and pressure P=1 bar

The maximum temperature = 13456 C

Compression ratio r= 12

We know that for process 1-2

\dfrac{T_2}{T_1}=r^{\gamma -1}

\dfrac{T_2}{303}=12^{1.4 -1}

T_2=818.68 K

Now for process 2-3

\dfrac{T_3}{T_2}=\dfrac{V_3}{V_2}

\dfrac{273+1345}{818.86}=\dfrac{V_3}{V_2}

\dfrac{V_3}{V_2}=1.97

So the cut off ratio ρ=1.97

Efficiency of diesel engine

\eta =1-\dfrac{\rho ^{\gamma}-1}{r^{\gamma -1}\gamma \left (\rho -1\right )}

Now put the values

\eta =1-\dfrac{1.97 ^{1.4}-1}{12^{1.4-1}\times 1.4\times \left (1.97 -1\right )}

   ⇒η=0.568

So the efficiency is 56.8%.

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To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

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Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

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Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

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3 0
3 years ago
"A fluid at a pressure of 7 atm with a specific volume of 0.11 m3/kg is constrained in a cylinder behind a piston. It is allowed
AlekseyPX

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4 years ago
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andrey2020 [161]

Answer:

10.984mm

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stress=loading/area                          area" cross-section"

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lateral strain=(-v)*axial strain= -0.31*0.00463

lateral strain= -1.4353*10^-3=change in diameter/ original diameter

change in diameter=(-1.4353*10^-3)*0.011= -1.57883*10^-5 m

negative indicates decrease in diameter.

decrease in dia.=0.01578mm

new diameter=11-0.01578= 10.984mm

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Answer:

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