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3 years ago

Will states ¨there is no number greater than .59 that has a 5 in the tenths place

1 answer:

6 0

Answer: there is a greater number for 59 with 5 tenths places but i'm sure what the other part of the answer could be but I gave you a few hints to this problem and I hope this helps you well.

Have a great weekend and the rest of your day.

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Homework

Zolol [24]

Note: As you have missed to mention the first four terms of the Arithmetic sequence. So, I am randomly assuming that first four terms of the arithmetic sequence be 1, 3, 5, 7... This would anyhow make you understand the concept. So, I am solving your query based on assuming the first four terms of an Arithmetic sequence as 1, 3, 5, 7...

Part A)

What is the next term of this sequence?

Answer:

${\displaystyle \ a_{5}=9$ is the next term i.e. 5th term of the arithmetic sequence 1, 3, 5, 7...

Step-by-step explanation:

Considering the Arithmetic sequence with fist four terms

1, 3, 5, 7...

As we know that a sequence is termed as arithmetic sequence of numbers if the difference of any two consecutive terms of the sequence remains constant.

For instance, 1, 3, 5, 7... will be an arithmetic sequence having the common difference 2. Common difference is denoted by 'd'.

So,

Given the sequence

1, 3, 5, 7...

$d=3-1=2,d=5-3=2$

As $a_{1} = 1$ and $d = 2$

The next term i.e. 5th term can be found by using the $nth$ term of the sequence.

So, consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Putting $n=5$ in, $a_{1} = 1$ and $d = 2$ in $\ a_{n}=a_{1}+(n-1)d$ to find the 5th term.

$\ a_{n}=a_{1}+(n-1)d$

$\ a_{5}=1+(5-1)2$

$\ a_{5}=1+(4)2$

${\displaystyle \ a_{5}=9$

So, ${\displaystyle \ a_{5}=9$ is the next term i.e. 5th term of the arithmetic sequence 1, 3, 5, 7...

Part B)

Writing down an expression, in terms of n for the nth term of the sequence

consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Here, $a_{1}$ is the first term, $d$ is the common difference.

For example,

Given the sequence

1, 3, 5, 7...

$d=3-1=2,d=5-3=2$

As $a_{1} = 1$ and $d = 2$

The next term i.e. 5th term can be found by using the $nth$ term of the sequence.

So, consider the nth term of the sequence $a_{n$

$\ a_{n}=a_{1}+(n-1)d$

Putting $n=5$ in, $a_{1} = 1$ and $d = 2$ in $\ a_{n}=a_{1}+(n-1)d$ to find the 5th term.

$\ a_{n}=a_{1}+(n-1)d$

$\ a_{5}=1+(5-1)2$

$\ a_{5}=1+(4)2$

${\displaystyle \ a_{5}=9$

Keywords: arithmetic sequence, nth term, common difference

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7 0

3 years ago

Susan invests $Z at the end of each year for seven years at an annual effective interest rate of 5%. The interest credited at th

aleksley [76]

Answer:

2.02955

Step-by-step explanation:

Given that:

Susan invests $Z as each year ends for seven years.

So we assume that Z = 1

Susan's accrued value comprises $7 invested each year at a 6 percent annual effective rate.

The cashflow interest:

The cashflow of Susan interest payments are:

Payments Time

0 1

0.05 2

2(0.05) 3

3(0.05) 4

4(0.05) 5

5(0.05) 6

6(0.05) 7

The accumulated value of this cash flow is:

$(0.05)I_{6\%} = (0.05) \dfrac{((1+0.06)_{6\%} - 6)}{0.06} \\ \\ \implies 1.1653$

So Susan accumulated values is:

X = 7 + 1.1653

X = 8.1653

Lori's accumulated value is $14, which she has set aside to plan her cash flow for interest.

The cashflow of Lori interest payments are;

Payments 0 0.025 2(0.025) 3(0.025) ......... 13(0.025)

Time 1 2 3 4 .......... 14

The accumulated value of cash flow is:

$(0.025 )(I)_{3\%} =(0.025) \dfrac{(1+0.03)_{3\%}-13}{0.03}\\ \\= 2.5719$

Now, Lori's accumulated value is:

Y = 14 + 2.5719

Y = 16.5719

Since; Susan value X = 8.1653

Lori's value Y = 16.5719

∴

$\dfrac{Y}{X}= \dfrac{16.5719}{8.1653}$

= 2.02955

7 0

3 years ago

At a store, Lauren selected a watermelon that weighed 38.4 ounces.

Mrrafil [7]

Answer:

$3.60

Step-by-step explanation:

1.50 ÷ 16 = 0.09375

there are 38.4 oz in laurens watermelon, so multiply the cost per ounce by the number of ounces to find the answer

0.09375 × 30.4 = 3.6

5 0

3 years ago

Help please!!!!!!!!!!!!!

zhuklara [117]

Answer= 13 _10= [23]_5
Please rewrite the same equation just put the 23 in the box

5 0

2 years ago

Explain why 2^0 is equal to 1.

weeeeeb [17]

Answer and Step-by-step explanation:

Anything that is to the power of 0 is equal to 1. This is why 2 to the power of 0 is equal to 0.

0 is the only number such that for any number x, x + 0 = x. So, the reason that any number to the zero power is one is because any number to the zero power is just the product of no numbers at all, which is the multiplicative identity, 1.

#teamtrees #PAW (Plant And Water)

3 0

3 years ago

Read 2 more answers