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Valentin [98]
2 years ago
14

HELP IM GIVING 20 POINTS LIKE PLZZ I NEED HELP​

Mathematics
1 answer:
maria [59]2 years ago
3 0

Answer:

price = 4.1

cost = 12.3

Step-by-step explanation:

price = 0.8+1.2+1.5+0.6 = p4.1

cost = 2.40+3.60+4.50+1.80 = $12.3

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Please don't give me a link<br><br> PLEASE HELPPP
KiRa [710]

Answer:

study more so you can understand

7 0
3 years ago
Solve for n <br> n + 6 = 12
zepelin [54]

Answer:

n=6

Step-by-step explanation:

12-6=6

4 0
3 years ago
Read 2 more answers
ANOTHER 20 POINTS
Mnenie [13.5K]

Answer:

$960

Step-by-step explanation:

1/5= .2

1-0.2= 0.8

1200×0.8= 960

7 0
3 years ago
Read 2 more answers
HELPPPP
fredd [130]

Not sure if this is correct but:

Step-by-step explanation: P = 2000

                                             R = 5% = 0.05

                                             n = 4

                                      y = 2000 ( 1 + \frac{0.05}{4}) ^{4t} = 2000 ( 1.0125 )

                                       Substitute values in the compound interest formula:

                                        y = P ( 1 + \frac{r}{n})^{nt} .

Hope this helps..                  

6 0
2 years ago
Determine the values of the constants b and c so that the function given below is differentiable. f(x)={2xbx2+cxx≤1x&gt;1
Lera25 [3.4K]
Assuming the function is

f(x)=\begin{cases}2x&\text{for }x\le1\\bx^2+cx&\text{for }x>1\end{cases}

For f(x) to be differentiable, it necessarily has to be continuous. For this condition to be met, we need

\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^+}f(x)=f(1)
\iff\displaystyle\lim_{x\to1}2x=\lim_{x\to1}(bx^2+cx)
\iff2=b+c

For the derivative to exist, the one-sided limits of the derivative must also exist and be equal. We have

f'(x)=\begin{cases}2&\text{for }x1\end{cases}

\displaystyle\lim_{x\to1^-}2=\lim_{x\to1^+}(2bx+c)
\iff2=2b+c

Now we solve for b and c:

\begin{cases}b+c=2\\2b+c=2\end{cases}\implies b=0,c=2
5 0
3 years ago
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