Find the volume of the following. Round to nearest hundredths place:

Mathematics

1 answer:

daser333 [38]3 years ago

8 0

Answer:

volume of cone=1/3×pi×r²×h

volume of cone =1/3×22/7×(2mi)²×7mi

volume of cone =29.32mi³

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Evaluate the function below for x=3<br><br> f(x)=2x^3-x^2-4x+9

elixir [45]

Hello,

f(x)=2x^3-x^2-4x+9=(((0+2)x-1)x-4)x+9

f(3)=(((0+2)*3-1)*3-4)*3+9=((2*3-1)*3-4)-3+9=(5*3-4)*3+9=11*3+9=33+9=42

or

f(3)=2*3^3-3^2-4*3+9=2*27-9-12+9=54-12=42

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3 years ago

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Inga [223]

Answer:

Terms=7a,3 Variables=a Coi=7 Constants=3

Step-by-step explanation:

Terms are the things you use in the equation.

Terms=7a, 3

Variables are the letters next to numbers

Variables= a

Coificents are numbers next to the variable.

Coi=7

Constants are numbers by themselves

Constants=3

7 0

2 years ago

Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.5 feet and a standard deviation o

Mumz [18]

Answer:

0% probability that the mean of the sample taken is less than 2.2 feet.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .