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3 years ago

Find the volume of the following. Round to nearest hundredths place:

Mathematics

1 answer:

daser333 [38]3 years ago

8 0

Answer:

volume of cone=1/3×pi×r²×h

volume of cone =1/3×22/7×(2mi)²×7mi

volume of cone =29.32mi³

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What is the answer 3y+6=-2x

Anika [276]

SOLVE FOR X (FIRST BOX) SOLVE FOR Y (SECOND BOX)

7 0

3 years ago

Which multiplication expression can be used to check this division problem:

borishaifa [10]

Answer:

° 3/2 × 4/15

Step-by-step explanation:

for checking a division problem use the product and one of the fractions to multiply. if the answer matches the other fraction then your division is correct.

6 0

3 years ago

Read 2 more answers

Evaluate the indefinite integral. (Use C for the constant of integration.) ex 5 ex dx.

melisa1 [442]

Answer:

$5 e^{x} +C$

where C is constant of integration

Step-by-step explanation:

Explanation:-

Given f(x) = 5 eˣ

Now integrating with respective to 'x' , we get

I = $\int\limits {5 e^{x} } \, d x$

By using integration formula

$\int\limits { e^{x} } \, d x = e^{x} +C$

$I = \int\limits {5 e^{x} } \, d x = 5 e^{x} +C$

where C is constant of integration

8 0

3 years ago

the ratio of cars to trucks on the parking lot is 2:3 there are 24 trucks on the lot what is the total number of vehicles on the

SVEN [57.7K]

x=16

Explanation

the ratio is 2:3

it means for every 2 cars, there are 3 trucks

Now, it the total of trucks is 24,the proportion must be the same, so

Step 1

Let

x represents the number of cars for 24 trucks

$\frac{\text{2 cars}}{3\text{ trucks}}=\frac{x}{24\text{ trucks}}$

Step 2

solve for x

$\begin{gathered} \frac{\text{2 cars}}{3\text{ trucks}}=\frac{x}{24\text{ trucks}} \\ 2\cdot24=3\cdot x \\ x=\frac{2\cdot24}{3} \\ x=\frac{48}{3} \\ x=16 \end{gathered}$

Hence, the answer is 16

4 0

1 year ago

Is {(1,2) (3,4) (5,8) (1,4)} a function?

MariettaO [177]

Given relation is not a function

Step-by-step explanation:

When a relation is given in the form of ordered pairs, the first element of each ordered pair is the member of domain set and second element is the member of range set.

In order for a relation to be a function, there should be no repetition in domain as the domain elements should be unique.

Given relation is:

{(1,2) (3,4) (5,8) (1,4)}

The domain is: {1,3,5,1}

As we can see there is repetition in domain i.e. 1 is twice in the set, the given relation is not a function.

Hence,

Given relation is not a function

Keywords: Domain, range

Learn more about domain at:

#LearnwithBrainly

5 0

3 years ago