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Zarrin [17]
3 years ago
10

A long-distance telephone company claims that the mean duration of long-distance telephone calls originating in one town was gre

ater than 9.4 minutes, which is the average for the state. Determine the conclusion of the hypothesis test assuming that the results of the sampling don’t lead to rejection of the null hypothesis.
(A) Conclusion: Support the claim that the mean is less than 9.4 minutes.
(B) Conclusion: Support the claim that the mean is greater than 9.4 minutes.
(C) Conclusion: Support the claim that the mean is equal to 9.4 minutes.
(D) Conclusion: Do not support the claim that the mean is greater than 9.4 minutes.
Mathematics
1 answer:
Setler [38]3 years ago
8 0

Answer:

(D) Conclusion: Do not support the claim that the mean is greater than 9.4 minutes

Step-by-step explanation:

Let X be the mean duration of long distance telephone class originating in one town.

H_0: x bar = 9.4\\H_a: x bar >9.4

(one tailed test)

The conclusion of the hypothesis test assuming that the results of the sampling don’t lead to rejection of the null hypothesis.

This means that there is no statistical evidence to support the alternate claim.

Hence option D is right.

(D) Conclusion: Do not support the claim that the mean is greater than 9.4 minutes

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The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

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I need help on my quiz!
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3 years ago
4 divided by 1/8 = <br> Please I’m taking math inventory lol
Angelina_Jolie [31]
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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