Answer:
OH HECK no im not that smart for this type of math , noo honeyboo
Step-by-step explanation:
Yh I think the missing number will be 6 because they are equivalent to 1:2
Answer:
4 trays should he prepared, if the owner wants a service level of at least 95%.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 5
Standard Deviation, σ = 1
We are given that the distribution of demand score is a bell shaped distribution that is a normal distribution.
Formula:

P(X > x) = 0.95
We have to find the value of x such that the probability is 0.95
P(X > x)
Calculation the value from standard normal z table, we have,
Hence, 4 trays should he prepared, if the owner wants a service level of at least 95%.
Answer:
12/30
Step-by-step explanation:
Here is the complete question
Three of these fractions are equivalent A.30/70 B.12/30 C.9/21 D.6/14 which one is the odd one out
to determine the equivalent fractions, convert the fractions to percentage
× 100 = 42.86%
× 100 = 40%
× 100 = 42.86%
x 100 = 42.86%
Another method is to convert the fraction to its simplest form
30/70
To transform to the simplest form. divide both the numerator and the denominator by 10 = 3/7
12/30
To transform to the simplest form. divide both the numerator and the denominator by 6 = 2/5
9/21
To transform to the simplest form. divide both the numerator and the denominator by 3 = 3/7
6/14
To transform to the simplest form. divide both the numerator and the denominator by 2 = 3/7
Using either methods, 12/30 is the odd one out
Answer:
(a) 315°
(b) 3°
(c) 238°
Step-by-step explanation:
Bearings are measured clockwise from north. The triangle described is illustrated in the attachment.
<h3>(a)</h3>
The bearing of P from R is 180° different from the bearing of R from P it will be ...
135° +180° = 315° . . . . bearing of P from R
__
<h3>(b)</h3>
The bearing of Q from R is 48° more than the bearing of P from R, so is ...
315° +48° = 363°, or 3° . . . . bearing of Q from R
__
<h3>(c)</h3>
The angle QPR has a value that makes the sum of angles in the triangle equal to 180°. It is ...
180° -48° -55° = 77°
The bearing of Q from P is 77° less than the bearing of R from P, so is ...
135° -77° = 58°
As above, the reverse bearing from Q to P is ...
58° +180° = 238° . . . . bearing of P from Q