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vodomira [7]
3 years ago
15

Determine which trig ratio you would use to find the height of the tree.

Mathematics
1 answer:
Viktor [21]3 years ago
3 0
Sin= p/h , cos= b/h , tan= p/b
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How does knowing the slope and y-intercept help you graph and write the equation of a line?
IgorLugansk [536]

Answer:

It allows to to know y-intercept formula which is used to graph a line.

Step-by-step explanation:

Y-intercept formula:

y=mx+b

  M: slope (keep in fraction if it is fraction, to help you graph)

  B: y-interecept

8 0
3 years ago
The graph shows two lines, A and B.
Papessa [141]
Part A: One solution because the lines intersect one time.
Part B: (3,4) or x=3 and y=4 (depending on how you have to write it)
8 0
2 years ago
On a storage warehouse, each container weighs 6^3 pounds. If there are 3 containers, how much do the crates weigh in total ?
PtichkaEL [24]

Answer: 72 pounds


Step-by-step explanation:

Basically (6*6*6) = 216

                            --------

                                3

                             = 72

5 0
3 years ago
Read 2 more answers
PLZ HELP GIVING BRAINLEST TO THE PERSON EHO EXPLAINS AND HAVE THE RIGHT ANSWER!
Andreyy89
It’s increased to 9. A square is equal on all sides.
4 0
3 years ago
The function f has a domain of {1, 3, 5, 7} and a range of {2, 4, 6}. Could f be represented by {(1, 2), (3, 4), (5, 6), (7, 2)}
bezimeni [28]

Answer:

Yes

Step-by-step explanation:

- Yes, a function with those domain and range values could certainly be represented by those points.

- (1,2) and (7,2) are points with separate domain values but identical range values: this is allowed because every x value is only assigned one y value (remember, one number x in domain cannot have two different numbers y in the range).

- Another way is the use of Vertical Line test of the curve passing through to the points  {(1, 2), (3, 4), (5, 6), (7, 2)}. sketch down multiple vertical lines passing through the curve. If any particular vertical line intersects the curve at more than one point on the curve then the curve is not a function of  y = f(x).

- You would see that all vertical lines are free this invalidation. Hence, y is a function of x having points  {(1, 2), (3, 4), (5, 6), (7, 2)}.

5 0
3 years ago
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