From the given tabular data,
Volume of water (V) = 50.0 ml
Mass of water (m) = 49.7 g
So, the density of water (ρ) = Mass / Volume
or, = 49.7 g /50.0 ml = 0.994 g / ml
<u>Actual value of the density of water (ρ') = 0.998 g /ml</u>
So, the percentage error in the density of water
= [( actual value - observed value) / actual value ] ×100
or, = [ (0.998 g /ml - 0.994 g / ml ) / 0.998 g /ml ] ×100
or, = 0.4 %
Hence, the required % error in the density of water will 0.4 %.
Answer:
Step-by-step explanation:
3^
The answer is to the question is b. 55
Yes...........................
How?
The area of a rectangle equals length times height. (A=LH)
A=256.5 L=18
Plugging in the numbers into the equation, you get 256.5=18H. (like I substituted the numbers in)
next if you divided both sides by 18, it will cancel out the 18 in the 18H side of the equation.
So, it is 256.5/18 equaling H
256.5 divided by 18 is... 14.25
That means the height is 14.25 an the length is 18.
the perimeter is all of the sides added together. in a rectangle, the sides opposite each other are the same.
So you have two sides that are 14.25 and two that are 18 meters long.
14.25+14.25+18+18 equals the perimeter then.
So the answer would be... 64.5!
