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Vitek1552 [10]
2 years ago
11

Donna is on the swim team. Each week she swims a total of 8000 meters. How many kilometers does she swim each week? Be sure to i

nclude the correct unit in your answer.
Mathematics
1 answer:
aivan3 [116]2 years ago
7 0

Answer:

Donna swims 8 km each week.

Step-by-step explanation:

To be able to find the answer, you have to consider that 1 km is equal to 1000 meters and with this, you can use  rule of three to find the kilometers in 8000 meters:

1 km  →  1000 meters

  x    ←   8000 meters

x=(1*8000)/1000=8 km

According to this, the answer is that Donna swims 8 km each week.

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1. Solve for w in the equation W/5 = 25<br> A.W = 5<br> B.W = 125<br> C. W = 30<br> D.W = 20
vekshin1

Answer: <em>w = 125</em>

Explanation: Since <em>w</em> is being divided by 5, to solve for <em>w</em>,

multiply both sides of the equation by 5.

On the left side, the 5's will cancel

and on the right side, 25(5) is 125.

So <em>w = 125</em>.

<u />

<u>Please do not do this problem in your head.</u>

Show the work that it takes to get <em>w</em> by itself.

3 0
3 years ago
Find the area of a triangle with sides of length 6 and 7 and included angle 74°. (round your answer to one decimal place.)
Yanka [14]
We use this formula:
<span>Area = ½ • side 1 • sine (A) • side 2
</span>Area = <span>½ • 6 • sine (74) • 7
</span><span>Area = <span>21 • sine (74)
Area = 21*0.96126
Area = </span></span><span><span><span>20.18646 </span> </span> </span>
Area = 20.2 (rounded)
Source:
http://www.1728.org/triang.htm


5 0
3 years ago
Listed below are prices in dollars for one night at different hotels in a certain region. Find the​ range, variance, and standar
Artyom0805 [142]

Answer:

Range = 115$

Standard Deviation = 43.76$

Variance = 1915.142$

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

Step-by-step explanation:

We are given the data for  prices in dollars for one night at different hotels in a certain region.

234, 160, 119, 131, 218, 207, 146, 141        

Range:

Sorted data: 119, 131, 141, 146, 160, 207, 218, 234

\text{Range} = 234-119 = 115\$

Standard Deviation:

\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}  

where x_i are data points, \bar{x} is the mean and n is the number of observations.  

Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}

Mean =\displaystyle\frac{1356}{8} = 169.5

Sum of squares of differences = 4160.25 + 90.25 + 2550.25 + 1482.25 +  2352.25 + 1406.25 + 552.25 + 812.25 = 13406

\sigma = \sqrt{\dfrac{13406}{7}} = 43.76\$

Variance =

\sigma^2 = 1915.142\$

Measure of variance for someone searching for room:

Option  A) The measures of variation are not very useful because when searching for a​ room, low​ prices, location, and good accommodations are more important than the amount of variation in the area.

5 0
3 years ago
How do you do this?
sammy [17]

its all about the angles just subtract the number you have from the total

5 0
3 years ago
After 7 years, Abner earned $1575 in simple interest from a CD into which he initially deposited $6000. What was the annual inte
Radda [10]
The answer is C. 3.75%
6 0
3 years ago
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