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2 years ago

Which equation represents a line which is perpendicular to the line y=2x-4?

Mathematics

1 answer:

11Alexandr11 [23.1K]2 years ago

3 0

So 1+1 is 2 3 equals 4 me and bae dated eachother last dau

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Help me on number 24 plss

chubhunter [2.5K]

The animal that shows the fastest change is the horse. The animal that shows that slowest rate of change is the mouse.
We can use graphs to find the rate of chabge by comparing. From using only the beginning and ending of the data, we would be finding the average rate of change over the specified period of time.
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7 0

3 years ago

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

6 0

3 years ago

If 8 gallons of gas cost $40, how much does 10 gallons of gas cost

insens350 [35]

8 costs 40 so 10 costs | 40 / 8 = ( 5*2=10) So your answer is 50 Dollars.

5 0

2 years ago

Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0

Debora [2.8K]

So, the definite integral $\int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74$

Given that

$\int\limits^1_0 {x^{2} } \, dx = 13$

We find

$\int\limits^1_0 {(4 - 6x^{2} )} \, dx$

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, $Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx$

So, $\int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - \int\limits^1_0 {6x^{2} } \, dx \\= 4[x]^{1}_{0} - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1] - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6\int\limits^1_0 {x^{2} } \, dx$