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kolezko [41]
2 years ago
14

Peter leaves his house and walks 15 meters south, then turns east and walks another 15 meters. How far is he from his house? Rou

nd your answer to the nearest tenth
Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
4 0
When Peter does this, he is creating two sides of a right-angle triangle. The distance from his house to that point will be the hypotenuse of the triangle thus, to work out the length of the hypotenuse, we have to use Pythagoras Theorem! So:

a² + b² = c²
15² + 15² = c²
225 + 225 = c²
450 = c²
15√2 = c
21.21320344 = c

So, this rounded to the nearest tenth would be:

21.2 meters !


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b. Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box.
Ainat [17]

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

<u>Step-by-step explanation:</u>

Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.

⇒ 2x

The third box contained two more pounds than the first box i.e.

⇒ x+2

The last box contained one-fourth the amount in the second box i.e.

⇒ (\frac{1}{4})2x = \frac{x}{4}

Therefore , Sum of pounds of candy are :

⇒ \frac{x}{2} +x+2+2x+x=65

⇒ \frac{x}{2} +4x=63

⇒ \frac{9x}{2}=63

⇒ x=63(\frac{2}{9} )

⇒ x=14

Therefore , Candy in each box is :

First box = 14 pounds

Second box = 2x = 28 pounds

Third Box = x+2= 16 pounds

Fourth box = x/2 = 7 pounds

8 0
3 years ago
X 6.4.5-T
butalik [34]

Same strategy as before: transform <em>X</em> ∼ Normal(76.0, 12.5) to <em>Z</em> ∼ Normal(0, 1) via

<em>Z</em> = (<em>X</em> - <em>µ</em>) / <em>σ</em>   ↔ <em>X</em> = <em>µ</em> + <em>σ</em> <em>Z</em>

where <em>µ</em> is the mean and <em>σ</em> is the standard deviation of <em>X</em>.

P(<em>X</em> < 79) = P((<em>X</em> - 76.0) / 12.5 < (79 - 76.0) / 12.5)

… = P(<em>Z</em> < 0.24)

… ≈ 0.5948

8 0
3 years ago
Plz help me I have no idea how to do this plz help!
Vika [28.1K]
You need to multiply the amount by the tax
8 0
3 years ago
Help!! I need an answer asap!! <br><br> Given a∥b, find m∠1 = 71º. <br> Find: m∠5, m∠8
Sindrei [870]

Answer:

m<5 = 71 and m<8 = 109

Step-by-step explanation:

m<1 is equivalent to m<5 and m<2 is equivalent to m<8.

5 0
2 years ago
Read 2 more answers
Write an equation of the line that passes through (−1,3) and is parallel to the line y=2x+2.
MA_775_DIABLO [31]

The equation of the line that passes through (−1,3) and is parallel to the line y = 2x + 2 in slope intercept form is y = 2x + 5

<h3><u>Solution</u>:</h3>

Given that line passes through (-1, 3) and parallel to line y = 2x + 2

We have to find the equation of the line

Let us first find the slope of the line

<em><u>The slope intercept form of line is given as:</u></em>

y = mx + c  ---- eqn 1

where "m" is the slope of the line and "c" is the y-intercept

Comparing the given line equation y = 2x + 2 with y = mx + c,

We get slope "m" = 2

The slope of parallel lines are equal

Hence slope of the line which is parallel to y = 2x + 2 is also 2

Now let us find the equation of line with slope "m" = 2 and passes through point (-1, 3)

Substitute (x, y) = (-1, 3) in eqn 1 to find value of "c"

3 = 2(-1) + c

3 = -2 + c

c = 5

Now substitute "c" = 5 and m = 2 in eqn 1 to get equation of required line

y = 2x + 5

Thus the equation of line in slope intercept form is y = 2x + 5

4 0
2 years ago
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