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kramer
4 years ago
8

Which of the following is not equal to 120 centimeters? 0.0012 kilometers (km) 0.012 dekameters (dkm) 1.2 meters (m) 1200 millim

eters (mm)
Chemistry
2 answers:
Masteriza [31]4 years ago
7 0
Dekametres
120/100
Answer/ 1000= km
120 x 10= mm =1200
Crazy boy [7]4 years ago
3 0

Answer:

0.012 Dekameters (mm) is not equal to 120 centimeters.

Explanation:

1 km = 1000 m

1 m = 100 cm

Then 1000 m will be equal to :

1000 m = 1000 × 100 cm = 100,000 cm

So, 1 km =  100,000 cm

Then 120 cm will be equal to: 0.0012 km

1 m = 100 cm

Then 120 cm will be equal to: 1.2 m

1 Dm = 1000 cm

Then 120 cm will be equal to: 0.12 Dm

1 cm = 10 mm

Then 120 cm will be equal to: 1,200 mm

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Compound W, C8H17Br, and X, C8H17Cl, are products of the radical bromination (W), and chlorination (X), of 2,4-dimethylhexane. W
oksian1 [2.3K]

Answer:

The possible structures are shown in figure.

Explanation:

The seven isomers that could be formed from the given compound due to radical halogenation are shown in the figure.

We have mentioned only chlorine as group for showing just the chiral nature of the compound.

A chiral compound has a carbon with all the four groups different from each other.

There are three structures which are chiral (as shown).

W is the brominated product

X is the chlorinated product.

1) W reacts readily in water to form a chiral substitution product Y, C8H17OH.

Reaction of a single enantiomer of W produces a single enantiomer of Y as the only substitution product.: It means that the substitution is SN2 which is possible if the compund is not tertiary.

2) X likewise reacts readily in water though at a slower rate than W; a chiral substitution product Z, C8H17OH, is again formed. Unlike W, however, reaction of a single enantiomer of X produces Z that is nearly racemic.

It means that it will undergo SN1 reaction,. So the alkyl halide must be tertiary.

The possible structures are shown in figure.

5 0
4 years ago
An unknown compound contains only C , H , and O . Combustion of 4.20 g of this compound produced 10.3 g CO 2 and 4.20 g H 2 O .
vodomira [7]

Answer:

C4H8O

Explanation:

We can get the answer through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 10.3/44 = 0.2341

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above

The mass of carbon in the compound is simply the number of moles multiplied by the atomic mass unit. The atomic mass unit of carbon is 12. The mass of carbon in the compound is thus 12 * 0.2341= 2.8091

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 4.2/18 = 0.2333

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.2333 = 0.4667 moles

The mass of hydrogen is thus 0.4667* 1 = 0.4667

The mass of oxygen equals the mass of the compound minus that of hydrogen and that of carbon.

= 4.2 - 0.4667 - 2.8091 = 0.9242

The number of moles of oxygen is the mass of oxygen divided by its atomic mass unit.

That equals 0.9242/16 = 0.0577625 moles

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of oxygen

H = 0.4667/0.0577625 = 8

O = 0.0577625/0.0577625 = 1

C = 0.2341/0.0577625 = 4

The empirical formula is thus C4H8O

5 0
3 years ago
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Angelina_Jolie [31]
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Softa [21]

Answer:

the heat energy is transformed to any kind of energy depending on what it's meant to be transformed to.

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