Carbon monoxide is a carbon atom bonded with an oxygen atom. Carbon dioxide is a carbon atom bonded with <em>two</em> oxygen atoms. That's it really, they have different properties but that is significantly more detailed and all a result of their molecular formula.
When PH = -㏒[H3O+]
and we have PH = 5.061
by substitution:
∴ [ H3O+] = 10^-5.061 = 8.7x10^-6
when we have Ka = [CH3COO-][H3O+] / [CH3COOH]
we have Ka = 1.8x10^-5 & [H3O+] = 8.7x10^-6m & [CH3COOH] = 0.5 m
by substitution in Ka formula:
1.8x10^-5 = [CH3COO-]*(8.7x10^-6) / 0.5
∴[CH3COO-] = 1.034
∴we need to add 1.034 mol of sodium acetate
Answer: 1.09 kPa
Explanation:
Given that,
Original volume V1 = 3.2 L
Original pressure P1 = 2.8 kPa
New pressure P2 = ?
New volume V2 = 8.1 L
Since pressure and volume are given While temperature is constant, apply Boyle's law
P1V1 = P2V2
2.8 kPa x 3.2L = P2 x 8.1L
8.96 kPa L = P2 x 8.2L
P2 = 8.96 kPa L / 8.2L
P2 = 1.09 kPa
Thus, the pressure of the gas would be 1.09 kPa
According to what is known about chemical equilibrium and Le Chatelier's principle, when you increase the amount of the reactants, the reaction will be moved to the products, this is because, the most reactants we have the most products we can produce.
From the given choices, the one that goes according to this reason is the third one: The volume of water vapor increases.