Compound W, C8H17Br, and X, C8H17Cl, are products of the radical bromination (W), and chlorination (X), of 2,4-dimethylhexane. W
and X are each chiral. W reacts readily in water to form a chiral substitution product Y, C8H17OH. Reaction of a single enantiomer of W produces a single enantiomer of Y as the only substitution product. X likewise reacts readily in water though at a slower rate than W; a chiral substitution product Z, C8H17OH, is again formed. Unlike W, however, reaction of a single enantiomer of X produces Z that is nearly racemic. Propose structures for W and X.
1 answer:
Answer:
The possible structures are shown in figure.
Explanation:
The seven isomers that could be formed from the given compound due to radical halogenation are shown in the figure.
We have mentioned only chlorine as group for showing just the chiral nature of the compound.
A chiral compound has a carbon with all the four groups different from each other.
There are three structures which are chiral (as shown).
W is the brominated product
X is the chlorinated product.
1) W reacts readily in water to form a chiral substitution product Y, C8H17OH.
Reaction of a single enantiomer of W produces a single enantiomer of Y as the only substitution product.: It means that the substitution is SN2 which is possible if the compund is not tertiary.
2) X likewise reacts readily in water though at a slower rate than W; a chiral substitution product Z, C8H17OH, is again formed. Unlike W, however, reaction of a single enantiomer of X produces Z that is nearly racemic.
It means that it will undergo SN1 reaction,. So the alkyl halide must be tertiary.
The possible structures are shown in figure.
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Answer : The correct option is, (A)
Explanation :
Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.
We can determine the van't Hoff factor by the association and dissociation of the compound.
(A)
It is an electrolyte that dissociates to give aluminum ion and chloride ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 3 = 4
(B)
It is an electrolyte that dissociates to give potassium ion and iodide ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2
(C)
It is an electrolyte that dissociates to give calcium ion and chloride ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 2 = 3
(D)
It is an electrolyte that dissociates to give magnesium ion and sulfate ion.
The dissociation of will be,
So, Van't Hoff factor = Number of solute particles = = 1 + 1 = 2
(E) Non-electrolyte
The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.
Hence, the highest van't Hoff factor of solute is,
Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is for
.
The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.
The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.
The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.
The combustion of octane can be given as:
Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is . Thus, option B is correct.
Learn more about enthalpy of reaction, here:
This is an incomplete question, here is a complete question.
Hydrogen and iodine react to form hydrogen iodide, like this:
Also, a chemist finds that at a certain temperature the equilibrium mixture of hydrogen, iodine, and hydrogen iodide has the following composition:
Compound Pressure at equilibrium
61.8 atm
46.5 atm
52.3 atm
Calculate the value of the equilibrium constant for this reaction. Round your answer to 2 significant digits.
Answer : The value of equilibrium constant for this reaction is, 0.952
Explanation :
The given chemical reaction :
The expression of for above reaction follows:
We are given:
Putting values in above equation, we get:
Therefore, the value of equilibrium constant for this reaction is, 0.952