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Yanka [14]
3 years ago
15

The calorimeter pictured below shows the final temperature after calcium chloride was added to water. (The initial temperature w

as 25°C.) Which of the following best describes what occurred within the calorimeter?
A. Only Bond forming occurred

B. The bonds that formed were the most part stronger than the bonds that were broken

C. More energy was absorbed in breaking bonds than was released when new bonds form

D. As the powder dissolved, the breaking of bonds released energy
Chemistry
2 answers:
creativ13 [48]3 years ago
7 0

Answer:

The answer is acctualy B

Explanation:

I did the gizmo

max2010maxim [7]3 years ago
3 0
It’s probably D or c
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What is the total number of atoms present in 5Na,PO.?
denis23 [38]

Answer:

3.01×10²⁴ atoms

Explanation:

Our compound is the Na₃PO₄

Sodium phosphate.

We assume, we have 5 moles of the mentioned salt.

1 mol of anything contains 6.02×10²³ atoms.

That's the Avogadro's number. The conversion is:

5 mol . 6.02×10²³ atoms /1mol = 3.01×10²⁴ atoms

6 0
3 years ago
Which transition in a hydrogen atom would absorb the photon of greatest frequency?1) n = 3 to n = 12) n = 6 to n = 23) n = 2 to
Nata [24]

Answer:

n .= 1 to 4

Explanation:

From the Planck 5

E = hc/lambda

Where lambda is wavelength

E= hf

We will explain the answer here with respect to wavelength. It should be understood that the higher the wavelength of transition, the lower the frequency.

This means that longer transitions will occur at lesser frequencies. From the options the biggest transition is from 2 to 94, while the smallest is from 1 to 4

The transition from 1 to 4 is expected to have the highest energy as it has the shortest wavelength,

Transition from 2 to 94 has the longest wavelength, lowest energy and least frequency

7 0
3 years ago
When 0.5141 g of biphenyl (C12H10) undergoes combustion in a bomb calorimeter, the temperature rises from 25.823 °C to 29.419 °C
natka813 [3]

Answer:

\Delta_{r}U of the reaction is -6313 kJ/mol

\Delta_{r}H of the reaction is -6312 kJ/mol

Explanation:

Temperature\,\,change= \Delta U = 29.419-25.823 =3.506^{o}C

q_{cal}= C \times \Delta T

=5.861 \times 3.596 = 21.076\,kJ

q_{rxn}= -q_{cal}= -21.076\,kJ

\Delta_{r}U= -21.076 \times \frac{154}{0.5141}= -6313\, kJ/mol

Therefore, \Delta_{r}U of the reaction is -6313 kJ/mol.

The chemical reaction in bomb calorimeter  is as follows.

C_{12}H_{10}(s)+\frac{27}{2}O_{2}(g)\rightarrow 12CO_{2}(g)+5H_{2}O(g)

Number\,of\,moles\Delta n=(12+5)-\frac{27}{2}=3.5

\Delta_{r}H=\Delta E+ \Delta n. RT

=-6313+3.5\times 8.314\times 10^{-3} \times 3.596=-6312\,kJ/mol

Therefore, \Delta_{r}H of the reaction is -6312 kJ/mol.

3 0
3 years ago
A 10.0-L rigid container holds 3.00 mol H2 gas at a pressure of 4.50 atm. What is the temperature of the gas?
prisoha [69]
We can approach this problem using the ideal gas law which is as follows:

PV = nRT

P = pressure
V = volume
n = number of moles
R = gas constant, 0.08206 Latm/Kmol
T = temperature

We are asked to solve for temperature and can rearrange the equation to solve for T:

PV = nRT
T = PV/nR

Now we simply plug in the data to solve for T:

T = (4.50 atm)(10.0 L)/(3.00 mol)(0.08206 Latm/Kmol)
T = 183 K

The temperature of the gas is 183 K.
3 0
3 years ago
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