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horrorfan [7]
3 years ago
13

Please answer each question if you can. I am taking a timed test and I do not understand.

Mathematics
2 answers:
iren [92.7K]3 years ago
7 0
For the first one, I am pretty sure 15/5 is wrong. All of the other ones equal 1.6 and 15/5 equals 3
belka [17]3 years ago
5 0

Answer:

the last one m equals 25

Step-by-step explanation:

125/25=5 5x5=25 5/25=25/125

You might be interested in
If the area of a circle measures 16 pi cm2, what is the circumference of the circle in terms of pi
Fiesta28 [93]

Answer: 8 pi

Step-by-step explanation: So we know that area of a circle is pi times r^2 so if we reverse that formula it would be square root of 16 pi which would be 4 pi and divide by pi so the radius is 4. And we know that the formula for circumference is 2 times pi times r, so 2 times 4 times pi is 8 pi. 8 pi is the cIrcumference! :)

7 0
3 years ago
You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp
Katena32 [7]
Let's move like a crab, backwards some.

after 2 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2

after 3 years?

\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3

is that enough to pay the $1100?


now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000   <---- standard form.
8 0
3 years ago
Ok need help this is the question :Use the Pythagorean theorem to write an equation for the distance Jane's trainer bikes.
IRINA_888 [86]

Answer:

<em>Jane traveled 8 miles farther then her trainer</em>

Step-by-step explanation:

<u>The Pythagora's Theorem</u>

In any right triangle, the square of the measure of the hypotenuse is the sum of the squares of the legs. This can be expressed with the formula:

c^2=a^2+b^2

Where

c = Hypotenuse or largest side

a,b = Legs or shorter sides

Jane's path from the Health Club to the end of her route describes two sides of a right triangle of lengths a=16 miles and b=12 miles.

Her total distance traveled is 16 + 12 = 28 miles

Her trainer goes directly from the Health Club to meet her through the hypotenuse of the triangle formed in the path.

We can calculate the length of his route as:

c=\sqrt{16^2+12^2}

c=\sqrt{256+144}=\sqrt{400}=20

c = 20 miles

The difference between their traveled lengths is 28 - 20 = 8 miles

Jane traveled 8 miles farther then her trainer

8 0
3 years ago
Help me with 4-9pleasw
stira [4]

Answer:

4. d= =  -0.5

9.  b= -2.2


8 0
3 years ago
Changing Bases to Evaluate Logarithms In Exercise, use the change-of-base formula and a calculator to evaluate the logarithm.
Ymorist [56]

Answer:

\frac{3}{2}

Step-by-step explanation:

Changing Bases to Evaluate Logarithms

log_{16}(64)

Apply change of base formula'

log_b(a)= \frac{log a}{log b}

log term should be the numerator and denominator is the log base

log_{16}(64)

log_{16}(a)= \frac{log 64}{log 16}

64 is 4^3  and 16 is 4^2

log_{16}(a)= \frac{log 4^3}{log 4^2}

Move the exponent before log

\frac{3log 4}{2log 4}

top and bottom has same log so cancel it out

\frac{3}{2}

3 0
3 years ago
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