Yes the diagonals of a parallelogram have the same midpoint since they ... of the intersection of the diagonals of parallelogram AB CD given the vertex points ... If a parallelogram is a rhombus then its diagonals are? , statement 2 is the answer
Each month that will give them 20$ for
Answer:
1443.36
Step-by-step explanation:
6014*.24=1443.36
Hope it helps
Next time, please share the answer choices.
Starting from scratch, it's possible to find the roots:
<span>4x^2=x^3+2x should be rearranged in descending order by powers of x:
x^3 - 4x^2 + 2x = 0. Factoring out x: </span>x(x^2 - 4x + 2) = 0
Clearly, one root is 0. We must now find the roots of (x^2 - 4x + 2):
Here we could learn a lot by graphing. The graph of y = x^2 - 4x + 2 never touches the x-axis, which tells us that (x^2 - 4x + 2) = 0 has no real roots other than x=0. You could also apply the quadratic formula here; if you do, you'll find that the discriminant is negative, meaning that you have two complex, unequal roots.
Answer:
6.5
Step-by-step explanation:
first subtract 7 from both sides
2x=13
next divide both sides by 2
x=6.5
