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3 years ago

14

How do you know if an agle is congruent

2 answers:

Trava [24]3 years ago

4 0

Answer:

Same angle measure in degrees

Step-by-step explanation:

As long as the angles in decrees stay the same they will be congruent.

hoa [83]3 years ago

3 0

Answer:

Angles are congruent if they have the same angle measure in degrees. Try this Adjust any angle below by dragging an orange dot at its ends. The other angle will change to remain congruent with it. Angles are congruent if they have the same angle measure in degrees.

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RSM Question, please help!

arlik [135]

Answer:

7/15 is greater than 5/11

Step-by-step explanation:

7/15= .4667

5/11= .454545

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3 years ago

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Fittoniya [83]

530(1+.144/12)(.06) = 32.18 so even that is less than 35
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3 years ago

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3 years ago

In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a

nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

$\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ}$ ;

$\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ}$ ;

$\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q$ .

Also,

$\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P$ in right triangle PBM.

Thus $\rm \angle{P\hat{B}M} = \angle C\hat{M}Q$ .

Additionally $\rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}$ .

Therefore $\rm \triangle PBM \sim \triangle MCQ$ .

$\rm \displaystyle BC = 2\;MC$ for M is the midpoint of segment BC.

$\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC$ .

$\rm \triangle PBM \sim \triangle MCQ$ implies that

$\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3$ .

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3 years ago

Work out the gradient of the line joining the points (2, 3) and (5,7)

Debora [2.8K]

Answer:

The gradient of the line joining the points $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ is $\frac{4}{3}$ .

Step-by-step explanation:

The gradient of the line joining two distinct point on a plane is represented by the slope of a secant line ( $m_{PQ}$ ), that is:

$m_{PQ} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$ (1)

If we know that $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ , then the gradient of the line is:

$m_{PQ} = \frac{7-3}{5-2}$

$m_{PQ} = \frac{4}{3}$

The gradient of the line joining the points $P(x,y) = (2,3)$ and $Q(x,y) = (5,7)$ is $\frac{4}{3}$ .

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3 years ago