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3 years ago

PLEASE ANSWER ASAP! please

Mathematics

1 answer:

FinnZ [79.3K]3 years ago

5 0

Answer:

3 ÷ 0.5

Step-by-step explanation:

Since each large square is 1 whole, and theirs five out of 10 columns that are distinctivly a different orange, it'd be 3 divided by 0.5.

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2 years ago

It's timed plzzz help!!!

Novay_Z [31]

Answer:

Last Choice / D

Step-by-step explanation:

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3 years ago

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Please help me with this question

san4es73 [151]

Step-by-step explanation:

Given: $f'(x) = x^2e^{2x^3}$ and $f(0) = 0$

We can solve for f(x) by writing

$\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx$

Let $u = 2x^3$

$\:\:\:\:du=6x^2dx$

Then

$\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du$

$\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k$

We know that f(0) = 0 so we can find the value for k:

$f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}$

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3 years ago

A local kids play sold 8 adult tickets and 9 child tickets for a total of $205. On day two they sold only 4 adult tickets and 3

Naya [18.7K]

Answer:

The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13

Step-by-step explanation:

Let x be the cost of 1 adult ticket

Let y be the cost of 1 child ticket

Cost of 8 adult tickets = 8x

Cost of 9 child tickets = 9y

We are given that A local kids play sold 8 adult tickets and 9 child tickets for a total of $205

So, 8x+9y=205 ----- 1

Cost of 4 adult tickets = 4x

Cost of 3 child tickets = 3y

We are given that 4 adult tickets and 3 child tickets for a total of $83.

4x+3y=83 ----2

Plot 1 and 2 on graph

8x+9y=205 -- Red line

4x+3y=83 -- Blue line

Intersection point provides the solution

So, Intersection point =(11,13)

So, The price of 1 adult ticket is $ 11 and price of 1 child ticket is $13

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