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3 years ago

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Eight Boxes each hold the same number of machine parts. Only one answer below shows the total number of parts for all eight boxe

s. circle your answer
A. 135
B. 128
C. 136
D.133
PLEASEE HELPP ASAP!! PLEASE HELPPPPP

2 answers:

Annette [7]3 years ago

4 0

Answer:

I think it is B

Step-by-step explanation:

vaieri [72.5K]3 years ago

3 0

B I had that same question

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Find the function y1 of t which is the solution of 121y′′+110y′−24y=0 with initial conditions y1(0)=1,y′1(0)=0. y1= Note: y1 is

strojnjashka [21]

Answer:

Step-by-step explanation:

The original equation is $121y''+110y'-24y=0$ . We propose that the solution of this equations is of the form $y = Ae^{rt}$ . Then, by replacing the derivatives we get the following

$121r^2Ae^{rt}+110rAe^{rt}-24Ae^{rt}=0= Ae^{rt}(121r^2+110r-24)$

Since we want a non trival solution, it must happen that A is different from zero. Also, the exponential function is always positive, then it must happen that

$121r^2+110r-24=0$

Recall that the roots of a polynomial of the form $ax^2+bx+c$ are given by the formula

$x = \frac{-b \pm \sqrt[]{b^2-4ac}}{2a}$

In our case a = 121, b = 110 and c = -24. Using the formula we get the solutions

$r_1 = -\frac{12}{11}$

$r_2 = \frac{2}{11}$

So, in this case, the general solution is $y = c_1 e^{\frac{-12t}{11}} + c_2 e^{\frac{2t}{11}}$

a) In the first case, we are given that y(0) = 1 and y'(0) = 0. By differentiating the general solution and replacing t by 0 we get the equations

$c_1 + c_2 = 1$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 0$ (or equivalently $c_2 = 6c_1$

By replacing the second equation in the first one, we get $7c_1 = 1$ which implies that $c_1 = \frac{1}{7}, c_2 = \frac{6}{7}$ .

So $y_1 = \frac{1}{7}e^{\frac{-12t}{11}} + \frac{6}{7}e^{\frac{2t}{11}}$

b) By using y(0) =0 and y'(0)=1 we get the equations

$c_1+c_2 =0$

$c_1\frac{-12}{11} + c_2\frac{2}{11} = 1$ (or equivalently $-12c_1+2c_2 = 11$

By solving this system, the solution is $c_1 = \frac{-11}{14}, c_2 = \frac{11}{14}$

Then $y_2 = \frac{-11}{14}e^{\frac{-12t}{11}} + \frac{11}{14} e^{\frac{2t}{11}}$

c)

The Wronskian of the solutions is calculated as the determinant of the following matrix

$\left| \begin{matrix}y_1 & y_2 \\ y_1' & y_2'\end{matrix}\right|= W(t) = y_1\cdot y_2'-y_1'y_2$

By plugging the values of $y_1$ and

We can check this by using Abel's theorem. Given a second degree differential equation of the form y''+p(x)y'+q(x)y the wronskian is given by

$e^{\int -p(x) dx}$

In this case, by dividing the equation by 121 we get that p(x) = 10/11. So the wronskian is

$e^{\int -\frac{10}{11} dx} = e^{\frac{-10x}{11}}$

Note that this function is always positive, and thus, never zero. So $y_1, y_2$ is a fundamental set of solutions.

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infra made a chicken dish for dinner she at an 18 Oz package of vegetables in a 14 oz package of rice to 14 oz of chicken what w

JulsSmile [24]

18 + 14 + 14 = 46 oz

Then there are 16 oz in a pound so we take 46 oz ÷ 16 oz and we get 46/16 in fraction form. Then we simplify this out and get 2 7/8 pounds.

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Answer:

its your first option.

Step-by-step explanation:

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Soo first apply the exponent rule (2^5)^1/3*1/4
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so (2^5)^1/12
then you apply the exponent rule again 2^5*1/2
so 5*1/12= 5/12
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State if the triangle is acute obtuse or right

Dmitrij [34]

Answer:

It should be obtuse.

Step-by-step explanation: if i'm not mistaken it has to be obtuse. sorry i'm still learning i'm a beginner but, i'm volunteering to help everyone anyways because i'm a very nice person.

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3 years ago

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