Let:
Vj = Speed of jane
Vm = Speed of mike
d = distance
t = time
Jane travels 7 mph less than 2 times as fast as Mike, therefore:
Vj = 2Vm - 7
Remeber:
distance = speed*time
Distance traveled by mike:
d=Vm*t = Vm*6
Distance traveled by jane:
d + 198 = Vj*6
where:
Vj = 2Vm - 7
d + 198 = (2Vm-7)*6
Now, let:
d=Vm*6 (1)
d + 198 = (2Vm-7)*6 (2)
Replace (1) into (2)
6Vm + 198 = 12Vm - 42
Subtract 6Vm from both sides:
6Vm + 198 - 6Vm = 12Vm - 42 - 6Vm
198 = 6Vm - 42
Add 42 to both sides:
198 + 42 = 6Vm - 42 + 42
240 = 6Vm
Divide both sides by 6:
240/6 = 6Vm/6
40 = Vm
Vm = 40mph
Replace Vm into this equation Vj = 2Vm - 7 :
Vj = 2(40) - 7 = 80 - 7 = 73mph
Answer:
the positive slope of the asymptote = 5
Step-by-step explanation:
Given that:
Using the standard form of the equation:
where:
(h,k) are the center of the hyperbola.
and the y term is in front of the x term indicating that the hyperbola opens up and down.
a = distance that indicates how far above and below of the center the vertices of the hyperbola are.
For the above standard equation; the equation for the asymptote is:
where;
is the slope
From above;
(h,k) = 11, 100
= 100
a = 
a = 10
b = 
b = 2
y = 5x-53 , -5x -57
Since we are to find the positive slope of the asymptote: we have
to be the slope in the equation 
= 
= 5
Thus, the positive slope of the asymptote = 5
There are two days of the week that start with S. That's already 2/7. But, we add on Monday and that gives us 3/7
The probability of the day being chosen as Monday or Saturday or Sunday is 3/7.
1. 3y=27
2. x-4=3
3. p+8=17
4. 1/2q=14
Of course, this statement is FALSE.
Let`s assume that a small town in Nevada had a population of 1,000.
When it lost 20% of its population:
1,000 * ( 1 - 0.2 ) = 1,000 - 0.8 = 800
After that the same town gained 20 % more people:
800 * ( 1 + 0.2 ) = 800 * 1.2 = 960
960 ≠ 1,000
In the end the town`s population was not the same as it was before the downturm.
