Terms are also expressions. No Some А All PLZ ANSWER FAST

Rudiy27

4/11 is 0.363636363636
And "36" just keeps repeating

5 0

3 years ago

The given function k is a composition of two functions m and n so that k(x) = (m ∘ n)(x). k (x) = StartFraction 2 Over RootIndex

kotykmax [81]

Answer:

$\frac{2}{\sqrt[4]{x} }$

Step-by-step explanation:

6 0

2 years ago

Can someone help me with this?

podryga [215]

The pink goes under the light blue then the dark blue goes under the pink cause it says finish :)

4 0

2 years ago

Read 2 more answers

Match the identities to their values taking these conditions into consideration sinx=sqrt2 /2 cosy=-1/2 angle x is in the first

BaLLatris [955]

Answer:

$\cos(x+y)$ goes with $-\frac{\sqrt{6}+\sqrt{2}}{4}$

$\sin(x+y)$ goes with $\frac{\sqrt{6}-\sqrt{2}}{4}$

$\tan(x+y)$ goes with $\sqrt{3}-2$

Step-by-step explanation:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

We are given:

$\sin(x)=\frac{\sqrt{2}}{2}$ which if we look at the unit circle we should see

$\cos(x)=\frac{\sqrt{2}}{2}$ .

We are also given:

$\cos(y)=\frac{-1}{2}$ which if we look the unit circle we should see

$\sin(y)=\frac{\sqrt{3}}{2}$ .

Apply both of these given to:

$\cos(x+y)$

$\cos(x)\cos(y)-\sin(x)\sin(y)$ by the addition identity for cosine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}-\frac{\sqrt{2}}{2}\frac{\sqrt{3}}{2}$

$\frac{-\sqrt{2}}{4}-\frac{\sqrt{6}}{4}$

$\frac{-\sqrt{2}-\sqrt{6}}{4}$

$-\frac{\sqrt{6}+\sqrt{2}}{4}$

Apply both of the givens to:

$\sin(x+y)$

$\sin(x)\cos(y)+\sin(y)\cos(x)$ by addition identity for sine.

$\frac{\sqrt{2}}{2}\frac{-1}{2}+\frac{\sqrt{3}}{2}\frac{\sqrt{2}}{2}$

$\frac{-\sqrt{2}+\sqrt{6}}{4}$

$\frac{\sqrt{6}-\sqrt{2}}{4}$

Now I'm going to apply what 2 things we got previously to:

$\tan(x+y)$

$\frac{\sin(x+y)}{\cos(x+y)}$ by quotient identity for tangent

$\frac{\sqrt{6}-\sqrt{2}}{-(\sqrt{6}+\sqrt{2})}$

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}}$

Multiply top and bottom by bottom's conjugate.

When you multiply conjugates you just have to multiply first and last.

That is if you have something like (a-b)(a+b) then this is equal to a^2-b^2.

$-\frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}+\sqrt{2}} \cdot \frac{\sqrt{6}-\sqrt{2}}{\sqrt{6}-\sqrt{2}}$

$-\frac{6-\sqrt{2}\sqrt{6}-\sqrt{2}\sqrt{6}+2}{6-2}$

$-\frac{8-2\sqrt{12}}{4}$

There is a perfect square in 12, 4.

$-\frac{8-2\sqrt{4}\sqrt{3}}{4}$

$-\frac{8-2(2)\sqrt{3}}{4}$

$-\frac{8-4\sqrt{3}}{4}$

Divide top and bottom by 4 to reduce fraction:

$-\frac{2-\sqrt{3}}{1}$

$-(2-\sqrt{3})$

Distribute:

$\sqrt{3}-2$

6 0

2 years ago

Find the axis of summetry and the Vertex of its graph. Y=x2/squared-8x

Vilka [71]

Answer:

Direction: Opens Up

Vertex:

(

4

,

−

18

)

(4,-18)

Focus:

(

4

,

−

71

4

)

(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

73

4

y=-734

Select a few

x

x values, and plug them into the equation to find the corresponding

y

y values. The

x

x values should be selected around the vertex.x

y

2

−

14

3

−

17

4

−

18

5

−

17

6

−

14

xy2-143-174-185-176-14

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

4

,

−

18

)

(4,-18)

Focus:

(

4

,

−

71

4

)

(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

73

4

y=-734

x

y

2

−

14

3

−

17

4

−

18

5

−

17

6

−

14

xy2-143-174-185-176-14

image of graph

3 0

2 years ago