Can somebody help me on number 2 or 3? Please explain as well. HELP ASAP :)

Flauer [41]

Answer:

a) 1 / 12

b) 1 / 4

Step-by-step explanation:

The events are independent since they do not affect each other. The total probability of two independent events is the product of the probabilities of the two events.

a) When rolling a die, there are 6 outcomes, the numbers 1 - 6. There is only 1 outcome where you can get a 2. Therefore, the probability of rolling a two is 1/6.

When flipping a coin, there are two ways it can land: heads or tails. And there is one outcome with heads. The probability of getting head would be 1 / 2.

To find the the total, you multiply the probabilities of the two events: 1 / 6 * 1 / 2 = 1 / 12

b) As stated before, when rolling a die, there are 6 outcomes, the numbers 1 - 6. There are 3 outcomes where she can roll an even number: the numbers 2, 4, or 6. So, the probability of rolling an even number is 3 / 6 or 1 / 2.

When flipping a coin, there are two ways it can land: heads or tails. And there is one outcome with tails. The probability of getting tails would be 1 / 2.

Now, you multiply the two probabilities to get the total probability: 1 / 2 * 1 / 2 = 1 / 4

5 0

3 years ago

PLEASE HELP

NeTakaya

Answer:

A rectangular prism in which BA = 20 and h = 6 has a volume of 120 units3; therefore, Shannon is correct

Step-by-step explanation:

step 1

Find the area of the base of the rectangular pyramid

we know that

The volume of the rectangular pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the base

H is the height of the pyramid

we have

$V=40\ units^{3}$

$H=6\ units$

substitute and solve for B

$40=\frac{1}{3}B(6)$

$120=B(6)$

$B=120/6=20\ units^{2}$

step 2

Find the volume of the rectangular prism with the same base area and height

we know that

The volume of the rectangular prism is equal to

$V=BH$

we have

$B=20\ units^{2}$

$H=6\ units$

substitute

$V=(20)(6)=120\ units^{3}$

therefore

The rectangular prism has a volume that is three times the size of the given rectangular pyramid. Shannon is correct

3 0

4 years ago

What is the domain of the relation?

Tresset [83]

Answer:

Domain: 3, 6, 8, 9, 7

Step-by-step explanation:

Domain: 3, 6, 8, 9, 7

(Domain, Range)

The domain of a function or relation is the set of all possible independent values the relation can take.

Hope this helps :)

6 0

3 years ago

Read 2 more answers

1. (a) Solve the differential equation (x + 1)Dy/dx= xy, = given that y = 2 when x = 0. (b) Find the area between the two curves

erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

$(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx$

$\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx$

$\ln|y| = x - \ln|x+1| + C$

When x = 0, we have y = 2, so we solve for the constant C :

$\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)$

Then the particular solution to the DE is

$\ln|y| = x - \ln|x+1| + \ln(2)$

We can go on to solve explicitly for y in terms of x :

$e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}$

(b) The curves y = x² and y = 2x - x² intersect for

$x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1$

and the bounded region is the set

$\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}$

The area of this region is

$\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}$

7 0

3 years ago

I need help please :,(

Ede4ka [16]

I think it’s the first one

4 0

3 years ago