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3 years ago

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A Cube is made of white materiel, but the exterior is painted black. If the cube is cut into 125 smaller cubes of exactly the sa

me size, how many of the cubes will have exactly 2 of their sides painted black.

1 answer:

g100num [7]3 years ago

7 0

Answer:m k k

Step-by-step explanation:

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By October 19th, Gordon had read 35 pages. Starting on October 20th, he decides to read the same number of pages each day until

PilotLPTM [1.2K]

Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.

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2 years ago

A prism is completely filled with 96 cubes that have edge length of 1/2 cm.

ch4aika [34]

I know this is kinda late, but...

You can solve this easily as long as you remember how to find the volume of a cube. v=a^3, when a means length. The length is 1/2 cm, or .5 cm.
So, v+.5^3, which equals .125 cm. Each cube has a that volume. Now, multiply that by how many actual cubes there are, 96.

96 * .125 = 12

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3 years ago

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In quadratic formula

lorasvet [3.4K]

x² - x - 12 = 0

$x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a}$

a = 1, b = -1, c = -12

$x = \dfrac{1 \pm \sqrt{(-1)^{2} - 4(1)(-12)}}{2(1)}$

x = 4 or -3

Answer: 4 or -3

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3 years ago

A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe

Finger [1]

Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle $\triangle ABC$ as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

$\angle A =49^\circ$

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

$cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}$

Where

a is the side opposite to $\angle A$

b is the side opposite to $\angle B$

c is the side opposite to $\angle C$

$\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m$

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

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3 years ago

Frank has a batting average of .255. Write this decimal as a fraction in simplest form.

Artist 52 [7]

9/40 because when you put it in fraction form its 225/1000 then you simplify!

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3 years ago

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