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pickupchik [31]

3 years ago

13

Lines l and m are parallel. Which angle is a corresponding angle with ∠5? ∠7 ∠6 ∠8

1 answer:

Amanda [17]3 years ago

5 0

Answer:

∠7

Step-by-step explanation:

Given that lines l and m are parallel, and line t (the transversal) runs across both lines, thus:

Angle 5 and angle 7 occupy the same relative position or corner. They have the same matching corners where the line intercepts. Therefore, both angles are said to be corresponding angles.

∠7 is a corresponding angle with ∠5. ∠7 = ∠5.

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3 years ago

What is 548.2 times 38.7

faust18 [17]

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What type of triangle is formed by joining the points D(7,3), E(8,1) and F(4,-1)

andreyandreev [35.5K]

Calculate the lengths of the sides of the triangle:

The triangle has three different sides, so it's a scalene triangle.

Now if c is the longest side of the triangle, and a and b are the shorter sides, then:

- if , the triangle is right

- if , the triangle is acute

- if , the triangle is obtuse

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6 0

3 years ago

An antique has a price tag of $150. The sales tax rate for the county is 8%. How much sales tax will be due?

vampirchik [111]

Answer:

12

Explanation:

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3 0

2 years ago

Find the derivative of sinx/1+cosx, using quotient rule

Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

$f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}$

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}$

Now we can simplify that:

$f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}$

And we know that:

cos^2(x) + sin^2(x) = 1

then:

$f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}$

4 0

3 years ago