I wish i could help but even if i knew the answer it wouldnt help because this was posted 3 days ago...sorry
Answer:
c) x² + 3x + 1
Step-by-step explanation:
-3 / 1 6 10 3
<u> </u><em><u>-3</u></em><u> -</u><em><u>9</u></em><u> -</u><em><u>3</u></em><u> </u>
1 3 1 0
Answer: x² + 3x + 1
Step 1: Carry down the first number 1 as it is
Step 2: Multiply 1 by -3 (1 * -3 = -3) and write this -3 under the next number 6 and then add. 6 + (-3) = 3
Step 3: Multiply this 3 by -3 (3 * -3 = -9) and write this -9 under the next number 10 and then add.10 +[-9] = 1
Step 4: Multiply 1 by -3 (1 * -3 = -3) and write this -3 under the next number 3 and then add. -3 +[-3] = 0
The answer is d - 2.5
This is 2.5 less than the number d
If d was 3 then d- 2.5 = 3 - 2.5 = 0.5
Happy to help!
100 pounds is the weight of 10,000 samples
To solve the exponential growth application question we proceed as follows;
suppose the time, t between 1993 to 2000 is such that in 1993, t=0 and in 2000, t=7.
Note theta the population is in millions;
The exponential formula is given by:
f(t)=ae^(kt)
where;
f(t) =current value
a=initial value
k=constant of proportionality
t=time
substituting the values we have in our formula we get:
132=127e^(7k)
132/127=e^(7k)
introducing the natural logs we get:
ln (132/127)=7k
k=[ln(132/127)]/7
k=0.0055
Thus our formula will be:
f(t)=127e^(0.0055t)
The population in 2008 will be:
f(t)=127e^(15*0.0055)=127e^(0.0825)=137.922
Thus the population in 2008 is appropriately 138 million.
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