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shtirl [24]
3 years ago
14

A company manufactures ball bearings for precision machines. The average diameter of a certain type of ball bearing should be 6.

0 mm. To check that the average diameter is correct, the company formulates a statistical test. a. What is the sampling distribution of the mean score x of a sample of 50 ball bearings given the standard deviation is 0.7 mm. b. State the null and alternative hypothesis. c. Suppose that one sample data gives x
Mathematics
1 answer:
Sindrei [870]3 years ago
6 0

Answer:

(a) =210

(b) = 0.11

Step-by-step explanation:

Sampling distribution of the mean = 50 × 6 × 0.7= 210

Now to get the null divide 0.7 by 6

This gives 0.11

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100 PTS:Please help me now plz plz
Alex Ar [27]

Answer:

x = 12

Step-by-step explanation:

We have a right triangle with hypotenuse 10 and the height 8.  Either the one on the left or the one on the right

We can find the base using the Pythagorean theorem

a^2 + b^2 = c^2

a^2 +8^2 = 10^2

a^2  +64 = 100

Subtract 64 from each side

a^2 = 100 -64

a^2 = 36

Take the square root of each side

a = 6

Now a is 1/2 of the total base of the big triangle.  It is identical since the triangles are equal

x = 2 * a

x = 2*6 = 12

4 0
3 years ago
Read 2 more answers
Square root of -1? PLEASE HELP
kolezko [41]

My understanding it would be letter ( i )  because it is imaginary.  

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3 years ago
Evaluate the expression below.<br> (8 - 7)- 4 + 3(-1)<br> 1<br> -7<br> -1<br> 7
Masja [62]

Answer:

answer is -1 according to calculation

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3 years ago
Melissa wants to check the accuracy the accuracy of the finance charge on her promissory note. She has a $6000, four-year loan a
ValentinkaMS [17]

Answer:

1. Melissa wants to check the accuracy of the finance charge on her promissory note. She has a $6,000, 4-year loan at an APR of 3.11%.

What is her monthly payment?

$133.10

5 0
3 years ago
I don’t understand this and I did take notes on this on the computer but I still don’t understand it.
Serggg [28]

Answer:

<em>I</em>'[−3, −2], <em>Q</em>'[2, 0], <em>?</em>'[0, 1], <em>E</em>'[−3, −1]

Step-by-step explanation:

The line of reflection is at <em>y = −</em><em>2</em>,<em> </em>so looking at the line and where the coordinates of the shape are, you will have this:

<em>I</em>[−3, −2] → <em>I</em>'[−3, −2] (on the line, so it remains the same)

<em>Q</em>[2, −4] → <em>Q</em>'[2, 0]

<em>?</em>[0, −5] →<em> </em><em>?</em>'[0, 1]

<em>E</em>[−3, −3] → <em>E</em>'[−3, −1]

I am joyous to assist you anytime.

3 0
4 years ago
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