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sesenic [268]
3 years ago
11

Which questions are statistical questions?

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Answer:

Which questions are statistical questions?

what is the number of students what is the height of each in my class?

how many servings of fruit did eat each day this month?

what is my height?

what is the highest temprature

of each month this year?

how many students from each school in this city love football?

Step-by-step explanation:

Need to include numerical values

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During it's first 50 days of growth a sunflower grows about 4 cm a day. Using this rate how many days will it take for the sunfl
Alex787 [66]
The answer is 15 days because
60 \div 4 = 15
4 0
3 years ago
You earn $20.00 per hour at your job. If you get a 10% raise at the end of each year, what will your hourly rate, h, be after 8
love history [14]
R is the rate (10%)
C=20, begiing rate
T=time=8

so

h=20(1+0.10)^8
h=20(1.1)^8
h=42.8718
ronnd

$42.87


D is answer

4 0
3 years ago
The sum of 4 consecutive odd numbers is 40.<br> What is the second number in this sequence?
Tcecarenko [31]

Answer:

7,9,11,13 = 40

Step-by-step explanation:

second number is 9

7 0
3 years ago
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When combining like terms what is -10r - 5r put together?
marysya [2.9K]

Answer:

-15r

Step-by-step explanation:

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3 years ago
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A newly discovered planet orbits a distant star with the same mass as the Sun at an average distance of 101 million kilometers.
Elden [556K]
Kepler's third law described the relation between semi-major axis (or average distance to the star) and the orbital period (how long it takes to complete one lap) as follows: 
                                           a^3 / p^2 = constant
In the case of our Solar system the constant is 1 
This means that, for this problem:
a^3 / p^2 = 1
p^2 = a^3
p = a^(3/2)
The semi major axis is given as 101 million km. We need to convert this into AU where 1 AU is approximately 150 million Km
101 million Km = (101x1) / 150 = 0.67 AU

Now, we substitute in the equation to get the orbital period as follows:
p = (0.67)^(3/2) = 0.548 earth years
3 0
3 years ago
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