Answer:
![E(\bar{x}) = 28520](https://tex.z-dn.net/?f=E%28%5Cbar%7Bx%7D%29%20%3D%2028520)
Standard error of mean = 689
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $28,520
Standard Deviation, σ = $5600
Mean of sampling distribution =
![E(\bar{x}) = \mu = 28520](https://tex.z-dn.net/?f=E%28%5Cbar%7Bx%7D%29%20%3D%20%5Cmu%20%3D%2028520)
As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.
Sample size, n = 66
Since the sample size is large, we can use normal distribution for approximation.
Standard error of mean =
![\displaystyle\frac{\sigma}{\sqrt{n}} = \frac{5600}{\sqrt{66}} = 689.31 \approx 689](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%20%5Cfrac%7B5600%7D%7B%5Csqrt%7B66%7D%7D%20%3D%20689.31%20%5Capprox%20689)
-2.6 I think is the correct answer
Answer:
35
Step-by-step explanation:
If it hasn't started X would be 0 so it be 35+45(0) that would give you 35.
A. -13
B. -45
C. 20
D. 84
E. 4
F. -4
G. -7
H. 48
Answer:
![T=9x-10](https://tex.z-dn.net/?f=T%3D9x-10)
Step-by-step explanation:
Let x be the number of games
Cost of 1 game = $9
Cost of x games = 9x
he gets a student discount of $10.
So, Cost after discount = 9x-10
Let the total cost be T
So, ![T=9x-10](https://tex.z-dn.net/?f=T%3D9x-10)
So, An equation to represent the total cost of playing laser tag including the discount is ![T=9x-10](https://tex.z-dn.net/?f=T%3D9x-10)