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RoseWind [281]
3 years ago
8

I need help please !!!

Mathematics
1 answer:
Zarrin [17]3 years ago
3 0

Answer:

1. it is given

2. the definition of angle bisector

3. the reflexive property

4. SAS

5. corresponding parts of congruent triangles are congruent

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A video game has 25 levels. At level one, a player has 5 points. Each additional level increases the player's points by 10. If
ozzi

Answer:

<u>B. (3,25)</u>

Step-by-step explanation:

x = level of the video game

y = number of points

At level 1, a player has 5 points.

At level 2, the player has 5 + 10 = 15 points

Therefore, we can use the function notation this way:

f(x) = 5x + 10

<u>The only ordered pair given that is from this function is:</u>

<u>B. (3,25)</u>

<u>f(3) = 5 * 3 + 10 </u>

<u>f(3) = 15 + 10 = 25</u>

The remaining three don't represent this function.

3 0
3 years ago
Triangle OWL was rotated to create triangle O'W'L'. Describe the transformation using details and degrees.
Alisiya [41]
I believe this is a rotation through an angle of +90°, anticlockwise, (counterclockwise), with the center of rotation origin(0,0)
To describe rotation we give the center of rotation and the rotation angle in degrees stating whether it is clockwise or counterclockwise.
8 0
3 years ago
Read 2 more answers
NO LINKS OR FILES!
Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}

(b) The velocity after 3 seconds is

v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}

(c) The particle is at rest when its velocity is zero:

\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

\displaystyle \int_0^8 |v(t)|\,\mathrm dt

By definition of absolute value, we have

|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}

7 0
2 years ago
I need help ASAP PLEASEE
Alex787 [66]

Answer:

9. 21

10. 70

11. 64

12. 31

13. 85

14. 31

double check the answer, i didnt use a calculator so might be wrong

4 0
3 years ago
An investment is currently worth 1.035×108 dollars . Thirty years ago, the investment was worth ​ 2.3×105 ​ dollars. How many ti
nevsk [136]

The correct option is:  B. 450

<u><em>Explanation</em></u>

Current value of the investment is  1.035\times 10^8 dollars and 30 years ago, the value of the investment was  2.3\times 10^5 dollars.

Suppose, the value of investment today is  n times greater than the value of the investment thirty years ago.

So, the equation will be........

n(2.3\times 10^5)=1.035\times 10^8\\ \\ n= \frac{1.035\times 10^8}{2.3\times 10^5}=0.45\times 10^3 = 450

Thus, the value of the investment today is 450 times greater than the value of the investment thirty years ago.

6 0
3 years ago
Read 2 more answers
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