Explanation:
5.00 mol H2O × (1 mol C6H12O6/6 mol H2O)
= 0.833 mol C6H12O6
5.00 mol H2O × (6 mol O2/6 mol H2O)
= 5.00 mol O2
Answer:
I believe this is called the 'molar mass'
The chemical make-up changes.
1. 2CaS + 2H2O --> Ca(HS)^2 + Ca(OH)^2
2. Au^2S^3 + 3H2 --> 2Au + 3H2S
Answer:
The free energy change for the reaction at 37.0°C is -8.741 kJ.
Explanation:
The free energy of the reaction is given by :
where,
= standard Gibbs free energy
R = Gas constant =
T = temperature in Kelvins
K = equilibrium constant
We have :

1 kJ = 1000 J
T = 37.0 C = 37 +273.15 K = 310.15 K
Ratio of concentrations of the products to the concentrations of the reactants =K = 21.9
![\Delta G=-16,700 J/mol+8.314J/K mol\times 310.15 K \ln[21.9]](https://tex.z-dn.net/?f=%5CDelta%20G%3D-16%2C700%20J%2Fmol%2B8.314J%2FK%20mol%5Ctimes%20310.15%20K%20%5Cln%5B21.9%5D)

The free energy change for the reaction at 37.0°C is -8.741 kJ.