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zlopas [31]
3 years ago
12

What are the spectator ions in 2H+ + SO42- + Ca2+ + 21 → CaSO4 + 2H+ + 21-?

Chemistry
2 answers:
ra1l [238]3 years ago
8 0

Answer:

B

Explanation:

baherus [9]3 years ago
7 0

Answer:

B. H⁺ and I

Explanation:

Spectator ions are ions that appear in both the reactant and product of a chemical reaction. This ions remain unchanged on both sides of the chemical equation, they simply remain the same as the reaction occurs.

From the equation:

2H⁺ + SO₄²⁻ + Ca²⁺ + 2I⁻   ⇒   CaSO₄ + 2H⁺ + 2I⁻

you can see that H⁺ and I⁻ ions remain unchanged as the reaction occurs. This spectator ions can be removed to form a net ionic equation. Removing the spectator ions gives:

SO₄²⁻ + Ca²⁺    ⇒   CaSO₄

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One of relatively few reactions that takes place directly between two solids at room temperature is In this equation, the in Ba(
yuradex [85]

Answer:

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.

Explanation:

Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)

The balance chemical equation is :

Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)

Mass of barium hydroxide octahydrate = 6.5 g

Moles of  barium hydroxide octahydrate = \frac{6.5 g}{315 g/mol}=0.020635 mol

According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of  barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:

\frac{2}{1}\times 0.020635 mol=0.04127 mol

Mass of 0.04127 moles of ammonium thiocyanate;

0.04127 mol\times 76 g/mol=3.136 g\approx 3.14 g

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate

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