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3 years ago

What are the spectator ions in 2H+ + SO42- + Ca2+ + 21 → CaSO4 + 2H+ + 21-?

Chemistry

2 answers:

ra1l [238]3 years ago

8 0

Answer:

Explanation:

baherus [9]3 years ago

7 0

Answer:

B. H⁺ and I

Explanation:

Spectator ions are ions that appear in both the reactant and product of a chemical reaction. This ions remain unchanged on both sides of the chemical equation, they simply remain the same as the reaction occurs.

From the equation:

2H⁺ + SO₄²⁻ + Ca²⁺ + 2I⁻ ⇒ CaSO₄ + 2H⁺ + 2I⁻

you can see that H⁺ and I⁻ ions remain unchanged as the reaction occurs. This spectator ions can be removed to form a net ionic equation. Removing the spectator ions gives:

SO₄²⁻ + Ca²⁺ ⇒ CaSO₄

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Which number should go in the blank? - H₂ + O2 -> 2H₂O O 2 3 1

nydimaria [60]

2 is the number as you need to balance the equation

8 0

3 years ago

When iron(III) oxide reacts with hydrochloric acid, iron(III) chloride and water are formed. How many grams of iron(III) chlorid

Aleksandr [31]

Answer: The mass of iron (III) chloride produced is 14.81 grams

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For iron(III) oxide:

Given mass of iron(III) oxide = 10.0 g

Molar mass of iron(III) oxide = 159.7 g/mol

Putting values in equation 1, we get:

$\text{Moles of iron(III) oxide}=\frac{10.0g}{159.7g/mol}=0.0626mol$

For hydrochloric acid:

Given mass of hydrochloric acid = 10.0 g

Molar mass of hydrochloric acid = 36.5 g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{10.0g}{36.5g/mol}=0.274mol$

The chemical equation for the reaction of iron (III) oxide and hydrochloric acid follows:

$Fe_2O_3+6HCl\rightarrow 2FeCl_3+3H_2O$

By Stoichiometry of the reaction:

6 moles of hydrochloric acid reacts with 1 mole of iron (III) oxide

So, 0.274 moles of hydrochloric acid will react with = $\frac{1}{6}\times 0.274=0.0456mol$ of iron (III) oxide

As, given amount of iron (III) oxide is more than the required amount. So, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

6 moles of hydrochloric acid produces 2 moles of iron (III) chloride

So, 0.274 moles of hydrochloric acid will produce = $\frac{2}{6}\times 0.274=0.0913moles$ of iron (III) chloride

Now, calculating the mass of iron (III) chloride from equation 1, we get:

Molar mass of iron (III) chloride = 162.2 g/mol

Moles of iron (III) chloride = 0.0913 moles

Putting values in equation 1, we get:

$0.0913mol=\frac{\text{Mass of iron (III) chloride}}{162.2g/mol}\\\\\text{Mass of iron (III) chloride}=(0.0913mol\times 162.2g/mol)=14.81g$

Hence, the mass of iron (III) chloride produced is 14.81 grams

7 0

3 years ago

The empirical formula of pyrogallol is C2H2O. Its molar mass is 126 g mol-1. What is the molecular formula?C4H4O2C2H6O3C6H6O3C2H

VARVARA [1.3K]

Answer:

The molecular formula of pyrogallol is: C6H6O3

Explanation:

Step 1: Data given

Empirical formula of pyrogallol is C2H2O

Molar mass of pyrogallol = 126 g/mol

Molar mass of Carbon (C) = 12 g/mol

Molar mass of hydrogen (H) = 1.01 g/mol

Molar mass of oxygen (O) = 16 g/mol

Step 2: Calculate molar mass of the empirical formula

2*12 + 2*1+ 16 = 42 g/mol

Step 3: Calculate the molecular formula

To find the molecular formule , we should multiply the empirical formula by n

n can be found by dividing molar mass of pyrogallol by the molar mass of the empirical formula

n = 126 g/mol / 42 g/mol ≈ 3

We should mulitply the empirica lformula by 3

3*(C2H2O) gives C6H6O3

if we calculate the molar mass now:

6*12 +6*1 + 3*16 = 126 g/mol

The molecular formula of pyrogallol is: C6H6O3

6 0

3 years ago

8. An ion with 5 protons, 6 neutrons, and a charge of 3+ has an

Slav-nsk [51]

Atomic number = The number of proton in an atom or ion so the right answer is 5!

5 0

3 years ago

Each equation is incorrect. find the errors, then rewrite and balance each equation. cl2 + nai → nacl2 + i nh3 → n + h2 na + o2

VikaD [51]

1) Balanced chemical reaction: Cl₂ + 2NaI → 2NaCl + I₂.
Chlorine and iodine are diatomic molecules.
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6 0

4 years ago