Everyday, make her/him learn 3-4 tables. After 3 days, give him/her a 'prize' for it. If that does not work, try teaching him 1 by 1 and memorize it.
Let the first number be A. and the second number B.
A + B=12-------equation1 and
A ×B =-64------eqn2
from eqn1,
A =12 - B
so put A=12-B into eqn 2
(12-B) ×B=-64
.12B-B^2=-64
B^2-12B-64=0
now use calculator to find the answer.
u will get two answers, but u haven't finished yet. if B is = X,
put Xinto A=12-B
to find the value of A.
and so the same for the second number.
<span>Equation at the end of step 1 :</span> (2x - 5 • (2x - 7y + 3)) + -8<span> :</span>Pulling out like terms :3.1 Pull out like factors :
-8x + 35y - 23 = -1 • (8x - 35y + 23)
Final result : -8x + 35y - 23
Answer: 6 cm
Step-by-step explanation:
Given: The ratio of the areas of two similar parallelograms is 4:9.
To find : The height of the bigger one if the smaller is of height 4 cm.
Let h be the height of the bigger one.
Since the areas of similar figures are proportional to the square of their corresponding sides.
Then, 
![\dfrac{16}{h^2}=\dfrac{4}{9}\\\\\Rightarrow\ h^2=\dfrac{9}{4}\times16\\\\\Rightarrow\ h^2=36\\\\\Rightarow\ h= 6\ cm\ \ \ \ \text{[ height cannot be negative.]}](https://tex.z-dn.net/?f=%5Cdfrac%7B16%7D%7Bh%5E2%7D%3D%5Cdfrac%7B4%7D%7B9%7D%5C%5C%5C%5C%5CRightarrow%5C%20h%5E2%3D%5Cdfrac%7B9%7D%7B4%7D%5Ctimes16%5C%5C%5C%5C%5CRightarrow%5C%20h%5E2%3D36%5C%5C%5C%5C%5CRightarow%5C%20h%3D%206%5C%20cm%5C%20%5C%20%5C%20%5C%20%5Ctext%7B%5B%20height%20cannot%20be%20negative.%5D%7D)
Hence, the height of bigger parallelogram = 6 cm
The slope of the line is 4/1 and the y-intercept is -1.
