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3 years ago

(02.03) if granola costs $2.20 per pound, how much does 0.8 pound of granola cost?

Mathematics

2 answers:

Igoryamba3 years ago

7 0

Answer: it's $1.76 baby lol that is your answer trust me

Karolina [17]3 years ago

5 0

2.20 per pound

2.20 x 0.80 = 1.76

0.8 pounds cost $1.76

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Find the value of x. 6 8 4 x

snow_tiger [21]

Answer:

3

Explanation:

4 is half of 8 on the right side, so that means X has to be half of 6, so it’s 3. Also, it couldn’t be 2 because it is too big, and it can’t be 4 because it isn’t the same length as the other 4, so it’s 3

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2 years ago

A student bought a juice drink for $2 and a sandwich the total was &6.50 how much was the sandwich

mel-nik [20]

Answer:

Step-by-step explanation:

you have to minus 6.50 by 2 and you get the answer the anwser is 4.5

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3 years ago

Somebody please explain this I have a major exam soon and I really need to know how to solve problems like this

nevsk [136]

Answer:

y = 2x - 3

Step-by-step explanation:

Step 1: Find the slope. You find the slope by using the formula y2-y1/x2-x1. (2, 1) and (4, 5) are our points. Let's find our values.

y2= 5

y1= 1

x2 = 4

x1 = 2

Plug in the numbers into the equation. 5 - 1 is 4. 4 - 2 is 2. 4/2 is 2. There. Our slope is 2.

Step 2: Find the b value. Keep in mind that an equation in point-slope form is y = mx + b, where m = the slope, and b = the y-intercept. For this part, you will plug in one of the points as x and y to find the b value. let's use point (4, 5)

The equation then becomes 5 = 2(4) + b. As we know, 2 * 4 is 8. Subtract 8 on both sides of the equation to cancel out the right side and isolate the b variable. 5 - 8 is -3. Even if you use the other point for the equation (1 = 2(2) +b), you should get the same answer of -3.

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3 years ago

Which of the following is NOT a linear factor of the polynomial function?

Natalija [7]

Answer:

Among the four choices, $(x + 5)$ is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let $a$ denote some constant. A linear factor of the form $(x - a)$ is a factor of a polynomial $f(x)$ if and only if $f(a) = 0$ (that is: replacing all $x$ in the polynomial $f(x) \!$ with the constant $a\!$ would give this polynomial a value of $0$ .)

For example, in the second linear factor $(x - 2)$ , the value of the constant is $a = 2$ . Verify that the value of $f(2)$ is indeed $0$ . (In other words, replacing all $x$ in the polynomial $f(x) \!$ with the constant $2$ should give this polynomial a value of $0\!$ .)

$\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}$ .

Hence, $(x - 2)$ is indeed a linear factor of polynomial $f(x)$ .

Similarly, it could be verified that $(x - 5)$ and $(x + 2)$ are also linear factors of this polynomial function.

Rewrite the first linear factor $(x + 5)$ in the form $(x - a)$ for some constant $a$ : $(x + 5) = (x - (-5))$ , where $a = -5$ .

Calculate the value of $f(5)$ .

$\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}$ .

$f(5) \ne 0$ implies that $(x - (-5))$ (which is equivalent to $(x + 5)$ ) isn't a linear factor of this polynomial function.

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2 years ago

Aul bought 10 reams of paper at the store for a total of $84 the tax on thepurchase was $4 what was the cost of each ream of pap

yKpoI14uk [10]

84+4/10
hope this helps

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3 years ago