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Gnom [1K]
2 years ago
6

What is the equation of the translated function, g(x), if

Mathematics
2 answers:
mart [117]2 years ago
6 0

Answer:

In all the options g(x) is translation of f(x)

Step-by-step explanation:

Translation of a function means it shifting either left or right.

or we can say change in variable x .

f(x) = a(x-h)^2+k gives translated by h unit to the right or left according to positive or negative sign of h respectively.

Here in option 1 ,on comparing we have h =-5 therefore its translated by 5 units to the left

in Option 2 : ,on comparing it is h =-2 therefore  translated to 2 unit to the left

In option 3 : , on comparing we have h =2  therefore translated to 2 units to the right.

In option 4 : ,on comparing we have h =5 therefore translated to 5 units to the right.

therefore in all the options f(x) is translated.

Sergeeva-Olga [200]2 years ago
5 0
<span>Translation of a function is moving of the function without changing the shape of the function and without any rotation. So, translating of function means moving its graph left or right in the dierction of the x or y-axes. The function is f(x)=x^2. All of given options are translation of this function,.</span>
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Calculate the next 3 terms and write the formula for the nth term for the following sequences. 24,11,-2
Serjik [45]

Answer:

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Step-by-step explanation:

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Use the value of the linear correlation coefficient r to find the coefficient of determination and the percentage ofthe total va
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Step-by-step explanation:

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3 years ago
What is the range of the equation
a_sh-v [17]

The range of the equation is y>2

Explanation:

The given equation is y=2(4)^{x+3}+2

We need to determine the range of the equation.

<u>Range:</u>

The range of the function is the set of all dependent y - values for which the function is well defined.

Let us simplify the equation.

Thus, we have;

y=2 \cdot 4^{x+3}+2

This can be written as y=2^{1+2(x+3)}+2

Now, we shall determine the range.

Let us interchange the variables x and y.

Thus, we have;

x=2^{1+2(y+3)}+2

Solving for y, we get;

x-2=2^{1+2(y+3)}

Applying the log rule, if f(x) = g(x) then \ln (f(x))=\ln (g(x)), then, we get;

\ln \left(2^{1+2(y+3)}\right)=\ln (x-2)

Simplifying, we get;

(1+2(y+3)) \ln (2)=\ln (x-2)

Dividing both sides by \ln (2), we have;

2 y+7=\frac{\ln (x-2)}{\ln (2)}

Subtracting 7 from both sides of the equation, we have;

2 y=\frac{\ln (x-2)}{\ln (2)}-7

Dividing both sides by 2, we get;

y=\frac{\ln (x-2)-7 \ln (2)}{2 \ln (2)}

Let us find the positive values for logs.

Thus, we have,;

x-2>0

     x>2

The function domain is x>2

By combining the intervals, the range becomes y>2

Hence, the range of the equation is y>2

7 0
3 years ago
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