Answer:
The only solution can be (0,-3) point.
Step-by-step explanation:
We have to judge whether the points in options are the solution to the graphed inequality or not.
The first point is (5,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The second point is (6,0) which not included in the shaded region of the graph. Hence, it can not be a solution.
The third point is (0,-5) which not included in the shaded region of the graph. Hence, it can not be a solution.
The fourth point is (0,-3). It is on the firm red line which is included in the shaded region of the graph. Hence, it is a solution.
Therefore, the only solution can be (0,-3) point. (Answer)
Answer:
Given statement is TRUE.
Step-by-step explanation:
Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.
We know that corresponding angles formed by transversal line are congruent.
Hence ∠JKL = ∠ MLK ...(i)
Now consider triangles JKL and MLK
JK = LM {Given}
∠JKL = ∠ MLK { Using (i) }
KL = KL {common sides}
Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.
Hence given statement is TRUE.
Answer: x=1
Step-by-step explanation: 6x+24=30
6x=6
x=1
