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3 years ago

What is h(x) =-3x2 - 6x + 5 written in vertex form?

Mathematics

2 answers:

sergeinik [125]3 years ago

6 0

Answer:

Step-by-step explanation:

MatroZZZ [7]3 years ago

5 0

Answer:

h(x) = -3(x + 1)^2 + 8

Step-by-step explanation:

h=-3x^2-6x+5 subtract 5 from both sides

h-5=-3x^2-6x divide both sides by -3

(5-h)/3=x^2+2x halve the linear coefficient, square it, add it to both sides....

(2/2)^2=1 add 1 to both sides...

(5-h+3)/3=x^2+2x+1, now the right side is a perfect square...

(8-h)/3=(x+1)^2 multiply both sides by 3

8-h=3(x+1)^2 divide both sides by -1

h-8=-3(x+1)^2 add 8 to both sides

h=-3(x+1)^2+8

h(x)= -3(x+1)^2+8

BRAINLIEST PLS!!!

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Brandi solved 16 / 5 by using a related multiplication expression. What multiplication expression did she is?

klemol [59]

The given question is wrong.

Question:

Brandi solved $\frac{1}{6}\div 5$ by using a related multiplication expression. What multiplication expression did she is?

Answer:

The related multiplication expression is $$\frac{1}{6}\times \frac{1}{5}$ .

Solution:

Given expression is $\frac{1}{6}\div 5$ .

We can write 5 as a fraction with denominator 1.

$$ \frac{1}{6}\div5=\frac{1}{6}\div \frac{5}{1}$

Using the fraction rule $$\frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$ ,

$$\frac{1}{6}\div \frac{5}{1}=\frac{1}{6}\times \frac{1}{5}$

Now multiply the fractions using the rule $$\frac{a}{b}\times \frac{d}{c}=\frac{a\times d}{b\times c}$ ,

$$\frac{1}{6}\times \frac{1}{5}=\frac{1\times1}{6\times5}$

Let us multiply the numbers in the numerator and denominator separately, we get

$$\frac{1\times1}{6\times5}=\frac{1}{30}$

Hence the related multiplication expression is $$\frac{1}{6}\times \frac{1}{5}$ .

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Step-by-step explanation:

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