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Mila [183]
3 years ago
11

What is h(x) =-3x2 - 6x + 5 written in vertex form?

Mathematics
2 answers:
sergeinik [125]3 years ago
6 0

Answer:

B

Step-by-step explanation:

MatroZZZ [7]3 years ago
5 0

Answer:

<em>h(x) = -3(x + 1)^2 + 8</em>

Step-by-step explanation:

<em>h=-3x^2-6x+5  subtract 5 from both sides</em>

<em />

<em>h-5=-3x^2-6x  divide both sides by -3</em>

<em />

<em>(5-h)/3=x^2+2x  halve the linear coefficient, square it, add it to both sides....</em>

<em />

<em>(2/2)^2=1 add 1 to both sides...</em>

<em />

<em>(5-h+3)/3=x^2+2x+1, now the right side is a perfect square...</em>

<em />

<em>(8-h)/3=(x+1)^2  multiply both sides by 3</em>

<em />

<em>8-h=3(x+1)^2  divide both sides by -1</em>

<em />

<em>h-8=-3(x+1)^2  add 8 to both sides</em>

<em />

<em>h=-3(x+1)^2+8</em>

h(x)= -3(x+1)^2+8

<em>BRAINLIEST PLS!!!</em>

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